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777dan777 [17]
4 years ago
11

Which term describes the molecule shown below h-c-c-h ethyne c2h2?

Chemistry
2 answers:
dlinn [17]4 years ago
5 0

Answer:

unsaturated alkyne

Explanation:

apex

Andru [333]4 years ago
4 0
Ethyne also known as Acetylene and is the simplest Alkyne belonging to  Unsaturated Hydrocarbons. It contains triple bond between two carbon atoms in a molecule. Carbon atoms in Acetylene are sp Hybridized and has a linear shape with bond angle of 180° is present between C-C-H bonds. This compound is also called as Binary Compound because it is made up of two elements i.e. Carbon and Hydrogen. The terminal Hydrogen in Acetylene is slightly Acidic in nature, and this compound can donate terminal proton to any strong base. These compounds generally give Electrophillic Addition Reactions.
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(Chemistry question)
Anastaziya [24]
So to answer this we will use the next procedure:
<span>First balance the equation:
2 C6H5OH + 15 O2 --> 12 CO2 + 6 H2O
Phenol (C6H5OH) reacts with O2 in a 2:15 ratio.
This means:
moles phenol 2 / moles O2 = 2 / 15
moles phenol = (2/15)*0.200 = 0.0267
Molar mass of phenol is 94 g/mol
Mass of phenol would = 0.0267*94 = 2.5 g
</span>I hope this can help
6 0
3 years ago
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7 0
3 years ago
You have a solution of 0.0020 M HCl. What is the pOH of the solution?
Makovka662 [10]

Answer:

pOH=11.3

Explanation:

pH= -log[H+]=-log[0.002]=2.7

pOH+pH = 14

pOH= 14-2.7=11.3

6 0
4 years ago
Read 2 more answers
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Llana [10]

Answer:

1. desert

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Explanation:

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8 0
3 years ago
KNO3(s) --&gt; K+(aq) + NO3-(aq)This reaction was carried out in a Styrofoam insulated calorimeter and the following data were r
nataly862011 [7]

Answer:

Equation correctly showing the heat of solution

KNO_3(s)+35.2 kJ \rightarrow K^+(aq) + NO_{3}^-(aq)

Explanation:

Mass of aqueous solution = m = 100 g

Specific heat of solution = c = 4.18 J/gºC

Change in temperature = \Delta T=T_f-T_i

ΔT = 21.6ºC - 30.0ºC = -8.4ºC

Heat lost by the solution = Q

Q = mc\Delta T

Q=100 g\times 4.18 J/g^oC\times (-8.4^oC)

Q = -3,511.2 J ≈ -3.51 kJ

Heat absorbed by potassium nitrate when solution in formed; Q'

Q' = -Q = 3.51 kJ

Moles of potassium nitrate , n= \frac{10.1 g}{101 g/mol}=0.1 mol

KNO_3(s)\rightarrow K^+(aq) + NO_{3}^-(aq)

The heat of solution =

\frac{Q'}{n}=\frac{3.5112 kJ}{0.1 mol}=35.1 kJ/mol

So, the equation correctly showing the heat of solution

KNO_3(s)+35.2 kJ \rightarrow K^+(aq) + NO_{3}^-(aq)

4 0
4 years ago
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