A solenoidal coil with 25 turns of wire is wound tightly around another coil with 310 turns. the inner solenoid is 25.0 cm long
and has a diameter of 2.00 cm. at a certain time, the current in the inner solenoid is 0.116 a and is increasing at a rate of 1.85 103 a/s. (a) for this time, calculate the average magnetic flux through each turn of the inner solenoid. wb (b) for this time, calculate the mutual inductance of the two solenoids. h (c) for this time, calculate the emf induced in the outer solenoid by the changing current in the inner solenoid. v
1 answer:
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Answer:
1/2 Hz
Explanation:
A simple harmonic motion has an equation in the form of
where A is the amplitude, is the angular frequency and
is the initial phase.
Since our body has an equation of x = 5cos(π t + π/3) we can equate and solve for frequency f
f = 1/2 Hz