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Ann [662]
3 years ago
13

A solenoidal coil with 25 turns of wire is wound tightly around another coil with 310 turns. the inner solenoid is 25.0 cm long

and has a diameter of 2.00 cm. at a certain time, the current in the inner solenoid is 0.116 a and is increasing at a rate of 1.85 103 a/s. (a) for this time, calculate the average magnetic flux through each turn of the inner solenoid. wb (b) for this time, calculate the mutual inductance of the two solenoids. h (c) for this time, calculate the emf induced in the outer solenoid by the changing current in the inner solenoid. v

Physics
1 answer:
Ymorist [56]3 years ago
6 0
(a) Image 1
(b) Image 2
(c) Image 3

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When you have two like charges in a line â where is the electric field the greatest? is there ever a point where the field will
Vesna [10]

The magnitude of the electric field will be the greatest at the point where it is closest,to its charges.

Yes ,there is a point where the field will be zero.

what is an electric field?

The region where an electrostatic force is experienced by a charged entity is known as the electric field at a point.

As per the principle of field lines and vectors,where the field lines are in a close manner together,the field will be strongest.However ,where the field lines are in a manner apart,the field will be the weakest.

As per the concept,the electric field will be the greatest at the point where it is closest to its charges.For like charges, the electric field will be zero closer to the smaller charge and will be along the line joining the two charges. For opposite charges of equal magnitude, there will not be any zero electric fields.

Thus,we can conclude that there will be a point where the electric field is zero

learn more about electric field from here: brainly.com/question/28197462

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4 0
1 year ago
What is the half-reaction that occurs at the cathode during the electrolysis of molten potassium bromide?
polet [3.4K]

The complete ionization of KBr into its constituents is:<span>
<span>KBr (s)  --->  K+ (aq)  +  Br- (aq)</span></span>

<span>
During electrolysis, oxidation takes place at the anode electrode. This means that an ion is stripped off its electron hence becoming more positive:
<span>2 Br- (aq)  --->  Br2 (g) + 2e- </span></span>

We can see that Bromine gas Br2 is evolved at the anode. 

<span>
<span>Meanwhile at the cathode, the reduction reaction occurs. Which means that the electron from the anode electrode is used to make an ion more negative:
<span>2K+ (aq)  +  2e-  --->  2K (s) </span></span>
Hence, through reduction, solid potassium is deposited on the plate.</span>

 

 

Half reactions:

<span>Anode: 2 Br- (aq)  --->  Br2 (g) + 2e- </span>                       

<span>Cathode: 2K+ (aq)  +  2e-  --->  2K (s) </span>

7 0
2 years ago
A pulse traveled the length of a stretched spring the pulse transferred...A)energy only B)mass only C)both energy and mass D) ne
xz_007 [3.2K]

Answer:

A

Explanation:

So a pulse is a part of a mechanical wave, and mechanical waves are energy transfer trough some medium, in this case a stretched spring. So the correct answer is (A) energy only. The pulse cant be transferred into mass.

8 0
2 years ago
A 0.07-kg lead bullet traveling 258 m/s strikes an armor plate and comes to a stop. If all of the bullet's energy is converted t
Lubov Fominskaja [6]

Answer:

temperature change is 262.06°K

Explanation:

given data

mass = 0.07 kg

velocity = 258 m/s

to find out

what is its temperature change

solution

we know here

heat change Q is is equal to kinetic energy that is

KE = 0.5 × m× v²   ...........1

here m is mass and v is velocity

KE = 0.5 × 0.07 × 258²

KE = 2329.74 J

and we know

Q = mC∆t     .................2

here m is mass and ∆t is change in temperature and C is 127J/kg-K

so put here all value

2329.74 = 0.07 × 127 × ∆t

∆t = 262.06

so temperature change is 262.06°K

7 0
3 years ago
A 92.0-kg skydiver falls straight downward with an open parachute through a vertical height of 325 m. The skydiver’s velocity re
Alborosie

Answer:

The work done is 293.0kJ

Explanation:

<u>Data</u>

  • Mass:   m=92.0kg
  • height:    h=325m
  • acceleration due to gravity:  g=9.81m/s^{2}

Non conservative force act

The work is:

W=ΔKE+ΔPE

KE and PE means kinetic energy and potential energy respectively.

The change in kinetic energy is 0, since the skydiver’s velocity remains constant.

Therefore

W=0+ΔPE

W=ΔPE

W=mgh

substitute the values

W=92.0kg*9.81m/s^{2} *325m\\W=293020J\\W=293.0kJ

5 0
3 years ago
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