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2 years ago

A mixture that appears to only contain 1 substance is a ?

Physics

2 answers:

WARRIOR [948]2 years ago

4 0

A mixture that appears to contain only one substance is a. homogenous mixture.

Gnesinka [82]2 years ago

4 0

It’s a homogenous mixture

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An object with velocity 141 ft/s has a kinetic energy of 1558.71 ftâˆ™lbf, on a planet whose gravity is 31.5 ft/s2. What is its

Sidana [21]

Answer:

The mass of the object is 5.045 lbm.

Explanation:

Given;

kinetic energy of the object, K.E = 1558.71 ft.lbf

velocity of the object, V = 141 ft/s

The kinetic energy of the object is calculated as;

$K.E = \frac{1}{2} mV^2\\\\mV^2 = 2K.E\\\\m = \frac{2K.E}{V^2} \\\\1 \ lbf = 32.174 \ lbm.ft/s^2\\\\m = \frac{2 \ \times \ 1558.71 \ ft.lbf \ \times \ 32.174 \ lbm.ft/s^2 }{(141 \ ft/s)2 \ \ \times \ \ \ \ 1 \ lbf\ }$

$m = \frac{(2 \ \times \ 1558.71 \ \times \ 32.174) \ lbm.ft^2/s^2 }{(141 )^2\ ft^2/s^2 }\\\\m = \frac{(2 \ \times \ 1558.71 \ \times \ 32.174) \ lbm }{(141 )^2 }\\\\m = 5.045 \ lbm$

Therefore, the mass of the object is 5.045 lbm.

6 0

3 years ago

PLEASE The weight of a girl is 600 N and the area of her one foot is 50 cm². What will be the pressure exerted by her o

Rus_ich [418]

Answer:

pressure=force/area

p=600/50

p=12

so 12Nm^-1

4 0

3 years ago

What is the use of force to move an object over a distance?

steposvetlana [31]

Answer:

In physics, work is defined as the use of force to move an object. For work to be done, the force must be applied in the same direction that the object moves. Work is directly related to both the force applied to an object and the distance the object moves. <em>[I HOPE THIS HELPS* PLS MARK ME BRAINLIEST]</em>

6 0

3 years ago

C) Explain relative velocity with examples.

Mnenie [13.5K]

Answer:

we encounter ocassion where one or more object move in the which is not stationary with respect to another example a boat is cross a river that is flowing at some rate of aeroplane encountring wind durning it motion

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3 years ago

A cyclist is travelling eastwards at a velocity

VMariaS [17]

Answer:

0.02 m/s^2

Explanation:

change in velocity= 4.5m/s - 2.3m/s = 2.2 m/s

acceleration= change in velocity/change in time

acceleration= 2.2/120= 0.0183

= 0.02 (to 2 significant figures)

8 0

2 years ago