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STALIN [3.7K]
3 years ago
8

Which of the following is a star that has begun to run out of fuel? A) Neutron star B) Red giant C) Stellar nebula D) White dwar

f .
Physics
1 answer:
Readme [11.4K]3 years ago
7 0
The answer is B.Red Giant

Red Giants are stars which already in a late stage of evolution. These stars no longer have enough hydrogen to fuel it's nuclear fusion

hope this helps

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Object A has a mass of 10 kg and is moving at a velocity of 2.0
luda_lava [24]

Answer:20kgm/s

Explanation:

Mass=10kg

Velocity=2m/s

Momentum=mass x velocity

Momentum=10 x 2

Momentum=20

Momentum=20kgm/s

4 0
3 years ago
In unit-vector notation, what is the torque about the origin on a particle located at coordinates (0 m, −3.0 m, 2.0 m) due to fo
irinina [24]

Answer:

The torque about the origin is 2.0Nm\hat{i}-8.0Nm\hat{j}-12.0Nm\hat{k}

Explanation:

Torque \overrightarrow{\tau} is the cross  product between force \overrightarrow{F} and vector position \overrightarrow{r} respect a fixed point (in our case the origin):

\overrightarrow{\tau}=\overrightarrow{r}\times\overrightarrow{F}

There are multiple ways to calculate a cross product but we're going to use most common method, finding the determinant of the matrix:

\overrightarrow{r}\times\overrightarrow{F} =-\left[\begin{array}{ccc} \hat{i} & \hat{j} & \hat{k}\\ F1_{x} & F1_{y} & F1_{z}\\ r_{x} & r_{y} & r_{z}\end{array}\right]

\overrightarrow{r}\times\overrightarrow{F} =-((F1_{y}r_{z}-F1_{z}r_{y})\hat{i}-(F1_{x}r_{z}-F1_{z}r_{x})\hat{j}+(F1_{x}r_{y}-F1_{y}r_{x})\hat{k})

\overrightarrow{r}\times\overrightarrow{F} =-((0(2.0m)-0(-3.0m))\hat{i}-((4.0N)(2.0m)-(0)(0))\hat{j}+((4.0N)(-3.0m)-0(0))\hat{k})

\overrightarrow{r}\times\overrightarrow{F}=-2.0Nm\hat{i}+8.0Nm\hat{j}+12.0Nm\hat{k}=\overrightarrow{\tau}

4 0
3 years ago
One reason why display rules differ across cultures is because ___________. A. values and beliefs differ across cultures B. some
Soloha48 [4]

Answer:

The correct answer would be C, certain display rules are more appropriate than others.

Explanation:

I hope this helps you:)

6 0
3 years ago
A 1.40 kg block is attached to a spring with spring constant 15.5 N/m . While the block is sitting at rest, a student hits it wi
slava [35]

Answer:

v = 3.08 m/s.

Explanation:

Given,

  • Initial velocity of the block = u = 43 cm/s = 0.43 m/s
  • mass of the block = m = 1.40 kg
  • spring constant = k = 15.5 N/m.
  • x = 0.650 m

At x = 0.650 m

Let 'a' be the acceleration of the block at x.

Total force due to the spring force on the blcok at x= kx

\therefore F_s\ =\ kx\\\Rightarrow ma\ =\ kx\\\Rightarrow a\ =\ \dfrac{kx}{m}\\\Rightarrow a\ =\ \dfrac{15.5\times 0.650}{1.40}\\\Rightarrow a\ =\ 7.19\ m/s^2

Hence the acceleration of the block at x is 7.19\ m/s^2.

Let 'v' be the velocity of the block at x.

From the kinematics,

v^2\ =\ u^2\ +\ 2ax\\\Rightarrow v\ =\ \sqrt{u^2\ +\ 2ax}\\\Rightarrow v\ =\ \sqrt{0.43^2\ +\ 2\times 7.19\times 0.650}\\\Rightarrow v\ =\ 3.08\ m/s.

Hence at the compression x = 0.650 m the velocity of the block is 3.08 m/s.

5 0
4 years ago
PLEASE HELP ITS DUE IN 30 minutes!!! which two statements explain why a student standing at the top of a step stool doesnt move
Lesechka [4]

Answer:

i think it is c and b

Explanation:

7 0
4 years ago
Read 2 more answers
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