Answer:
(a) 
(b) 
Explanation:
The average power is defined as the amount of work done during a time interval:
According to work-energy theorem, the work done is equal to the change in kinetic energy. So, we have:
Recall that the weight is given by:
The car accelerates uniformly from rest (
). Replacing (3) in (2), we have:
(a) Finally, we replace this in (1):
(b)
Answer:
The speed of the car after the break was applied is 90.46 m/s
Explanation:
Given;
initial velocity of the car, u = 26.8 m/s
accelertation of the car, a = -8.2 m/s²
time of motion, t = 14.3 s
final velocity, v = ?
Apply the following kinematic equation;
v = u + at
v = 26.8 + (-8.2 x 14.3)
v = 26.8 - 117.26
v = -90.46 m/s
magnitude of the final velocity = 90.46 m/s
Therefore, the speed of the car after the break was applied is 90.46 m/s
metres to kilometres = 1/1000
8 m ⇒ 0.008 km
metres to centimetres = × 100
8 m ⇒ 800 cm
Answer:
41.3 m/s^2 option (e)
Explanation:
force, F = 6.81 N
mass, m = 165 g = 0.165 kg
Let a be the acceleration of the puck.
Use newtons' second law
Force = mass x acceleration
6.81 = 0.165 x a
a = 41.27 m/s^2
a = 41.3 m/s^2
Thus, the acceleration of the puck is 41.3 m/s^2.
How would you describe the behavior of particles in a solid?
