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3 years ago

This is a measure of force per unit area.

Physics

1 answer:

Vlad1618 [11]3 years ago

5 0

<h2>Answer: Pressure</h2>

<u>Pressure</u> is the force $F$ exerted by a gas, a liquid or a solid on a surface (or area) $A$ .

Its unit according to the International System of Units is Pascal $Pa$ which is equal to $N/m^{2}$ and its formula is:

$P=\frac{F}{A}$

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You travel 20.0 mph for 0.500 hour, 40.0 mph for 1.00 hour, 30.0 mph for 0.500 hour, and 50.0 mph for 2.00 hours. What is the av

Karo-lina-s [1.5K]

The answer is 41.25 mph.

The average speed (v) can be expressed as:
v = D/T
where
D is total distance: D = d1 + d2 + d3 + d4
T is total time: T = t1 + t2 + t3 + t4

Now let's calculate distances using the formula: d = v * t:
d1 = v1 * t1 = 20.0 * 0.500 = 10 mi
d2 = v2 * t2 = 40.0 * 1.00 = 40 mi
d3 = v3 * t3 = 30.0 * 0.500 = 15 mi
d4 = v4 * t4 = 50.0 * 2.00 = 100 mi

Thus, the average speed is:
$v= \frac{D}{T}= \frac{d1 + d2 + d3 +d4}{t1+t2+t3+t4} = \frac{10+40+15+100}{0.500+1.00+0.500+2.00}= \frac{165}{4} = 41.25 mph$

4 0

2 years ago

A 50.0 mg sample of an unknown radioactive substance was placed in storage and its mass measured periodically. After 19.7 days,

PilotLPTM [1.2K]

<h2>Answer: 4.928 days </h2><h2 />

Explanation:

This problem can be solved using the <u>Radioactive Half Life Formula: </u>

<u></u>

$A=A_{o}.2^{\frac{-t}{h}}$ (1)

Where:

$A=3.13mg$ is the final amount of the material

$A_{o}=50mg$ is the initial amount of the material

$t=19.7days$ is the time elapsed

$h$ is the half life of the material (the quantity we are asked to find)

Knowing this, let's substitute the values and find $h$ from (1):

$3.13mg=(50mg)2^{\frac{-19.7days}{h}}$ (2)

$\frac{3.13mg}{50mg}=2^{\frac{-19.7days}{h}}$ (3)

Applying natural logarithm in both sides:

$ln(\frac{3.13mg}{50mg})=ln(2^{\frac{-19.7days}{h}})$ (4)

$-2.77=-\frac{19.7days}{h}ln(2)$ (5)

Clearing $h$ :

$h=\frac{-19.7days}{-2.77}(0.693)$ (6)

Finally:

$h=4.928days$

6 0

3 years ago

I need help with this kind of science

kodGreya [7K]

Answer:

MG XD

Explanation:

N NDGJUDFRHTYUEEEEEEDFYdryuyhjftduftgfvguftyurthdfhyud

7 0

2 years ago

Read 2 more answers

What is the thinnest film (but not zero) of MgF2 (n = 1.38) on glass that produces a strong reflection for orange light with a w

Art [367]

The concept required to solve this problem is related to thin film interference.

The path length difference between two waves one is reflected from top surface of the film and the bottom surface of the film is equal to twice the thickness of the film:

$\gamma = 2t$

Where,

$\gamma =$ Path length difference

t = thickness

At the same time we have that the constructive interference condition for a thin film interference for strongly reflected rays is

$\gamma = m\lambda$

Where

$\gamma =$ Path length difference

$\lambda =$ wavelength

m = Any integer (order of the equation) which represent the number of repetition of the spectrum

Equation both expression we have

$2t = m\lambda$

Re-arrange to find the thickness we have

$t = m\frac{\lambda}{2n}$

Our values are given as

m = 1

$\lambda$ = 597nm

n = 1.38

Replacing,

$t = (1)\frac{597}{2(1.38)}$

$t = 216.3nm$

Therefore the thinnest thickness of the film is 216.3nm

6 0

2 years ago

How can to sticks quickly start a fire

LekaFEV [45]

Answer:

The closest thing to "rub bing two sticks together" is the hand-drill. You will need a fireboard (a small cedar board is good) and a thin, straight stick.

Explanation:

8 0

2 years ago