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VikaD [51]
3 years ago
5

If a ball is dropped from a height of 10 m, hits the ground and bounces back up to a maximum height of 7.5 m, describe how the E

nergy Pie Chart would look. (Use fractions and the storage mode)
In the same situation as above, how would the pie chart look at a height of 5 m (after the bounce but before the max height of 7.5)? (Use fractions and the storage mode)

______

A cart is speeding on a flat surface towards a spring mounted on a wall. As the cart moves, it slows. When the slowing cart hits the spring, it compresses it fully and the cart comes to rest. If the system consists of the cart, spring, and Earth's field, describe the transfer of energy at the initial and final points.
Physics
1 answer:
Greeley [361]3 years ago
8 0

Answer:hmmmm

Explanation:

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Which would exert the most gravity on a spacecraft that is passing close to Jupiter?
klio [65]
D. Jupiter has the highest amount of gravity in our solar system
7 0
2 years ago
Have an electrical charge of +1, while
Scrat [10]

Answer:

B

Explanation:

Protons have a positive electrical charge of +1,

Electrons have a negative charge of -1,

Neutrons have a neutral charge of about 0.

4 0
3 years ago
A coffee filter of mass 1.2 grams dropped from a height of 1 m reaches the ground with a speed of 0.8 m/s. How much kinetic ener
iren [92.7K]

<u>Answer:</u> The energy gained by the air molecules is 0.011 J.

<u>Explanation:</u>

Law of conservation of energy states that energy can neither be created nor be destroyed but it can only be transformed from one form to another form.

Here, the potential energy of the coffee filter is getting converted into kinetic energy of the coffee filter and some energy is lost by it which is gained by the air molecules in the form of kinetic energy.

So, calculating the potential energy of coffee filter, we use the equation:

P = mgh

where,

m = mass of coffee filter = 1.2 g = 1.2\times 10^{-3}kg    (Conversion used: 1 kg = 1000 g)

g = acceleration due to gravity = 9.8m/s^2

h = height of coffee filter = 1 m

Putting values in above equation, we get:

P=1.2\times 10^{-3}kg\times 9.8m/s^2\times 1m\\\\P=1.176\times 10^{-2}J

  • Calculating the kinetic energy of coffee filter, we use the equation:

E=\frac{1}{2}mv^2

where,

m = mass of coffee filter = 1.2 g = 1.2\times 10^{-3}kg

v = speed of coffee filter = 0.8 m/s

Putting values in above equation, we get:

E=\frac{1}{2}\times 1.2\times 10^{-3}kg\times (0.8m/s)^2\\\\E=3.84\times 10^{-4}J

As, energy lost by coffee filter = energy gained by air molecules

So, energy lost by coffee filter = Potential energy - Kinetic energy

Energy lost by coffee filter = (1.176\times 10^{-2})-(3.84\times 10^{-4})=0.011J

Hence, the energy gained by the air molecules is 0.011 J.

5 0
3 years ago
Which describes reproducibility? The ability of data to be published. The ability of data to be duplicated. The ability of data
olasank [31]

Answer:

the ability of data to be duplicated well described reproducibility

Explanation:

Reproducibitity of a data is the ability of a data to be produced in multiple times using the same procedure. It is used to test how precise a data is and it's usually known as standard deviation

Reproducibility is the closeness of the understanding between the consequences of measurements of the equivalent measurand did with a similar procedure depicted in the relating logical proof (for example a distribution in a companion surveyed diary).

3 0
3 years ago
Read 2 more answers
A space vehicle is traveling at 5425 km/h relative to the Earth when the exhausted rocket motor (mass 4m) is disengaged and sent
lana66690 [7]

Answer:

V_{cE}=1489m/s

Explanation:

Given data

Space vehicle speed=5425 km/h relative to earth

The rocket motor speed=81 km/h  and mass 4m

The command has mass m

From the conservation of momentum as the system isolated

p_{i}=p_{f}\\

Since the motion in on direction we can drop the unit vector direction

MV_{i}=4mV_{mE}+mV_{CE}

Where M is the mass of space vehicle which equals to sum of the motors mass and command mass.

The velocity of the motor relative to the earth equals the velocity of the motor relative to command plus the velocity of the command relative to earth

V_{mE}=V_{mc}+V_{cE}

Where Vmc is the velocity of motor relative to command

This yields

5mV_{i}=4m(V_{mc}+V_{cE})+mV_{cE}\\5V_{i}=4V_{mc}+5V_{cE}

Substitute the given values

V_{cE}=\frac{5V_{i}-4V_{mc}}{5}\\ V_{cE}=5425*\frac{1000}{60*60}(m/s)-\frac{4}{5}*81\frac{1000}{60*60}(m/s)\\  V_{cE}=1489m/s

5 0
3 years ago
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