Answer:
Option C. Time for one Earth rotation would double.
Explanation:
If the distance between Earth and Sun is increased up then it will decrease the gravitational pull of the Sun and hence will increase the orbital period of the Earth and will also increase the time taken for one Earth rotation because rotation of Earth is primarily depend on the external torque from the gravity of the Sun, Moon and other celestial bodies.
Stirring a solute into a solvent speeds up the rate of dissolving because it helps distribute the solute particles throughout the solvent. Hopefully this helps!
Answer:
660J/kg.°C
Explanation:
Using the fact that
∆E of metal + ∆E of water = 0
∆E of the metal = Q = m*c*(T2-T1)
Where
Q = heat lost or gained = ?
m = mass of metal in kg = 0.076kg
c = specific heat of the metal = ?
T1 = 96°C
T2=31°C
∆E of the water=Q= m*c*(T2-T1)
Where
Q = 0.120*4180*6.5 = 3260J
Therefore
3,260J + Q of the metal =0
3,260J + 0.076*C*(31.0–96.0)=0
3,260J - 4.94c = 0
3,260 = 4.94c
3,260/4.94 = c
660J/kg.°C = specific heat of the metal
hope this helps:)
Answer:
a) 21.133 minutes for series
b) 84.54 minutes when split into 4
Explanation:
Data provided:
Total flow, V₀ = 45 MGD
total volume of each basin, V = 2500 m³
Now,
1 MGD = 3785.4118 m³/day
also,
1 day = 1440 minutes
thus,
45 MGD = 45 × 3785.4118 m³/day
or
45 MGD = 170343.5305 m³/day
and,
170343.5305 m³/day in 'm³/min'
= 170343.5305 / 1440
= 118.2941 m³/min.
Therefore,
The retention time, t =
or
The retention time, t =
or
The retention time, t = 21.13 min
Hence,
for series of tanks the retention time is 21.133 min.
Now,
on splitting the tanks in 4
the volumetric flow rate will be
=
= 29.57 m³/min.
Therefore,
The retention time =
or
The retention time, t =
or
The retention time, t = 84.54 min
Answer:
tiny openings called the stomata.
Explanation: