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Alex
3 years ago
9

Calculate the percent water in each of the following hydrates:

Chemistry
1 answer:
koban [17]3 years ago
8 0
A) 40.5%
B) 44%
C) 28.9%
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Please help!
cluponka [151]
IT IS D FOCAL POINT
P.S. im in middle school not trying to brag

3 0
3 years ago
Read 2 more answers
PLEASE HELP WILL REWARD BRAINLIEST
riadik2000 [5.3K]
The answer is the principal quantum number

Hope this helps
7 0
3 years ago
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Use dimensional analysis to convert 4.68 g of Boron to cubic centimeters of Boron. The density of Boron is 2.34 g/cm^3
harina [27]

Answer:

The cubic centimeter of boron is 2.

Explanation:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Symbol:

The symbol used for density is called rho. It is represented by ρ. However letter D can also be used to represent the density.

Given data:

mass of boron = 4.68 g

density  of boron = 2.34 g/cm³

volume = ? (cm³)

Solution:

d = m/ v

v = m/d

v = 4.68 g/ 2.34 g /cm³

v = 2 cm³

8 0
3 years ago
According to the following reaction, how many grams of water are
slamgirl [31]

Answer:

H2O = (1×2) + ( 1×16)

2+ 16

= 18

<u>22.9</u>

18

1.27

I don't know this answer is right or wrong.

so please ask it from your another friend.

6 0
3 years ago
In the reaction H2SO4 + 2 NaOH -&gt; Na2SO4 + 2H2O, an equivalence point occurs when 32.23 mL of 0.2423 M NaOH is added to a 37.
stepladder [879]
The reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O applies to an acid-base titration.
            moles NaOH = c · V = 0.2423 mmol/mL · 32.23 mL = 7.809329 mmol
            moles H2SO4 = 7.809329 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 3.9046645 mmol
Hence
            [H2SO4]= n/V = 3.9046645 mmol / 37.21 mL = 0.1049 M
The answer to this question is  [H2SO4] = 0.1049 M
5 0
3 years ago
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