Answer:
False
because I got that question and I gotted right
The magnitude of the force exerted by the left cube on the right cube is 17.64N.
<h3>What is frictional force?</h3>
When an object is moving on a rough surface, it experiences opposition. This opposing force is called the friction.
Two identical 3.0-kg cubes are placed on a horizontal surface in contact with one another. The cubes are lined up from left to right and a force F₁ is applied to the left side of the left cube causing both cubes to move at a constant speed v. The coefficient of kinetic friction between the cubes and the surface is 0.3.
From the equilibrium of forces in vertical direction
Normal force N= 2m x g
friction force f = μN =μ(2m)g
From the equilibrium of forces in horizontal direction
F₁ =ma =0
using Newton's third law of motion, we get
F₁ - f =0
F₁ =f = μ(2m)g
Put the values, we get
F₁ = 17.64N
Thus, magnitude of the force exerted by the left cube on the right cube is 17.64N.
Learn more about friction force.
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Complete Question
The complete question is shown on the first uploaded image
Answer:
The wavelength is 
Explanation:
From the question we are told that
The distance of the slit to the screen is 
The order of the fringe is m = 6
The distance between the slit is 
The fringe distance is 
Generally the for a dark fringe the fringe distance is mathematically represented as
![Y = \frac{[2m - 1 ] * \lambda * D }{2d}](https://tex.z-dn.net/?f=Y%20%20%3D%20%5Cfrac%7B%5B2m%20%20-%201%20%5D%20%2A%20%20%5Clambda%20%2A%20%20D%20%20%7D%7B2d%7D)
=> ![\lambda = \frac{Y * 2 * d }{[2*m - 1] * D}](https://tex.z-dn.net/?f=%5Clambda%20%20%3D%20%20%5Cfrac%7BY%20%2A%20%202%20%2A%20%20d%20%7D%7B%5B2%2Am%20%20-%20%201%5D%20%2A%20%20D%7D)
substituting values
=> ![\lambda = \frac{0.019 * 2 * 0.9*10^{-3} }{[2*6 - 1] * 5}](https://tex.z-dn.net/?f=%5Clambda%20%20%3D%20%20%5Cfrac%7B0.019%20%2A%20%202%20%2A%20%200.9%2A10%5E%7B-3%7D%20%7D%7B%5B2%2A6%20%20-%20%201%5D%20%2A%20%205%7D)
=> 
<span>Falcon 9</span><span>Pegasus</span><span>Proton</span><span><span>Satellite </span><span>Launch </span>Vehicle</span><span>Antares</span><span>Zenit</span><span>Atlas V</span><span>Soyuz</span><span>Ariane 5</span><span>Delta IV</span><span><span>Polar Satellite </span><span>Launch </span>Vehicle</span><span><span>Geosynchronous </span><span>Satellite </span>Launch Vehicle</span><span>Vega</span><span>Rokot</span><span>Angara</span><span>Soyuz-2</span><span>Shavit</span><span>H-IIB</span><span>Dnepr</span><span>Safir</span><span>Falcon 1</span><span><span>Long March </span>4B</span><span><span>Long March </span>2D</span><span>Delta II</span><span>H-II</span><span><span>Long March </span>3C</span><span>Soyuz-U</span><span><span>Long March </span>4C</span><span>Black Arrow</span><span><span>Long March </span>3A</span><span>Naro-1</span><span>Zenit-3SL</span><span>Sputnik</span><span><span>Long March </span>2F</span><span>VLS-1</span><span>Vulcan</span><span><span>Long March </span>2C</span><span>Athena</span><span><span>Long March </span>3B</span><span>Juno I</span><span>N1</span><span>Ariane 6</span><span>Kuaizhou</span><span>Zenit-2</span><span>Simorgh</span><span><span>Long March </span>11</span><span>Strela</span><span>Minotaur-C</span><span>Ariane 1</span><span><span>Augmented </span><span>Satellite </span>Launch Vehicle</span><span>Europa<span>
</span></span>
Answer:
the answer is d
Explanation:
from F=Q1Q2
r².
then wen both charges are doubled
F=2Q1 ×2Q2
r²
F=4Q1Q2
r²
then 4 has to be the factor multiplied by the other part of the equation for it to balance
4F=4Q1Q2
r²
so theoretically the 4 on the LHS can cancel the 4 on the RHS
