Newton's second law states that the force applied to an object is equal to the product between the mass m of the object and its acceleration a:
Using
and
, we can find the value of the force applied to the roller-blade to obtain this acceleration:
Answer:
n = 5 approx
Explanation:
If v be the velocity before the contact with the ground and v₁ be the velocity of bouncing back
= e ( coefficient of restitution ) = 
and
h₁ is height up-to which the ball bounces back after first bounce.
From the two equations we can write that
So on
= .00396
Taking log on both sides
- n / 2 = log .00396
n / 2 = 2.4
n = 5 approx
The force decreases due to less frictional resistance. it becomes easier to keep it moving as it is already moving, one of the Newton's laws
