Reactivity. It is the ability of matter to combine chemically with other substances.
0.498 moles of copper(II) phthalocyanine would be produced by
the complete cyclotetramerization of 255 grams of phthalonitrile in the
presence of excess copper(ll) chloride.
<em>Copper(ll) phthalocyanine (Cu(C₃₂H₁₆N₈)) is produced by the cyclotetramerization of phthalonitrile (C₈H₄N₂) according to the following reaction: 4 C₈H₄N₂(l) + CuCl₂(s) → Cu(C₃₂H₁₆N₈)(s) + Cl₂(g) How many moles of copper(II) phthalocyanine would be produced by the complete cyclotetramerization of 255 grams of phthalonitrile in the presence of excess copper(II) chloride?</em>
Let's consider the following balanced equation.
4 C₈H₄N₂(l) + CuCl₂(s) → Cu(C₃₂H₁₆N₈)(s) + Cl₂(g)
The molar mass of C₈H₄N₂ is 128.13 g/mol. The moles corresponding to 255 g of C₈H₄N₂ are:

The molar ratio of C₈H₄N₂ to Cu(C₃₂H₁₆N₈) is 4:1. The moles of Cu(C₃₂H₁₆N₈) produced from 1.99 moles of C₈H₄N₂ are:

0.498 moles of copper(II) phthalocyanine would be produced by
the complete cyclotetramerization of 255 grams of phthalonitrile in the
presence of excess copper(ll) chloride.
You can learn more about stoichiometry here: brainly.com/question/22288091
Answer:
1.750×10^-6 g
Explanation:
we know n is 10^-9. all you have to do is to replace n with 10^-9.
so the answer is
1.750×10^3×10^-9 g
which is equal to 1.750×10^-6 g
if anything is unclear, ask freely.
I don't know much about this, but probably the reason why your teacher circled 300k is because of what's in the photo below. If you couldn't tell from the photo, its because 300k isn't negative. Anyway this is my guess, based on my limited knowledge.
Answer:

Explanation:
Hello,
In this case, by knowing that we have 1 billion (
1,000,000,000) of atoms of sulfur, via the Avogadro's number we can firstly compute the moles:

Then, by using the atomic mass of sulfur (32 g/mol), we can finally compute the mass:

Best regards.