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salantis [7]
3 years ago
10

Which has more mass, a mole of water (H2O) or a mole of glucose (C6H12O6)? a. water b. glucose c. The masses are the same

Chemistry
1 answer:
riadik2000 [5.3K]3 years ago
8 0
The correct answer is A
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(NEED HELP ASAP)
zheka24 [161]
1&3 are the answers lmk if it’s wrong
8 0
3 years ago
Consider these equations: 2S(s)+3O2(g)→2SO3(g) , ΔH=−792kJ 2S(s)+2O2(g)→2SO2(g) , ΔH=−594kJ 2SO2(g)+O2(g)→2SO3(g) , ΔH=? What is
Elenna [48]

Hess law can help us to obtain the enthalpy of a series of reactions by summation. The missing enthalpy of this reaction is −198kJ.

<h3>What is  Hess law?</h3>

According to the Hess law of constant heat summation, the enthalpy of a sequence of reactions can be obtained as the sum of the enthalpies of all the reactions.

Now looking at all the reavtion written here in order to obtain the missing enthalpy, we conclude that the missing enthalpy is −198kJ.

Learn more about enthalpy: brainly.com/question/3393755

6 0
2 years ago
Please help thank you (15 points)
sashaice [31]

Answer:

If the answer helps you PLEASE mark me as brainliest

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6 0
3 years ago
Suppose you held two magnets a short distance apart,then let go. what would happen?
Murljashka [212]
The two magnets ought to join together given that at least, if not both, have a strong enough magnetic force to do so.
4 0
3 years ago
Read 2 more answers
A sample of carbon dioxide has a pressure of 1.2 atm, a volume of
GalinKa [24]

The answer for the following question is mentioned below.

<u><em>Therefore no of moles present in the gas are 1.12 moles</em></u>

Explanation:

Given:

Pressure of gas (P) = 1.2 atm

Volume of a gas (V) = 50.0 liters

Temperature (T) =650 K

To calculate:

no of moles present in the gas (n)

We know;

According to the ideal gas equation;

We know;

<u>P × V = n × R × T </u>

where,

P represents pressure of the gas

V represents volume of the gas

n represents no of the moles of a gas

R represents the universal gas constant  

where the value of R is 0.0821 L atm  mole^{-1}  K^-1

T represents the temperature of the gas

As we have to calculate the no of moles of the gas;

n = \frac{P*V}{R*T}

n = \frac{1.2*50.0}{0.0821*650}

n = \frac{60}{53.365}

n = 1.12 moles

<u><em>Therefore no of moles present in the gas are 1.12 moles</em></u>

3 0
3 years ago
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