<span>A fault slip is the distance of motion, or displacement, along a fault during an earthquake. They can be classified by their relation to the horizontal, for example, if the fault slip happens primarily vertically it is a dip slip.</span>
Answer:
due to heaviness
Explanation:
because metal is heavier than water
Answer:
Part(a): The required change in angular displacement will be
.
Part(b): The angular displacement will be increased by a factor of 2.
Explanation:
If
,
,
and
represents the initial angular velocity, the final angular velocity , the angular acceleration and the change of angular displacement s, then from angular kinematic equation, we can write
![\omega_{f}^{2} = \omega_{i}^{2} + 2~\alpha~\delta \theta](https://tex.z-dn.net/?f=%5Comega_%7Bf%7D%5E%7B2%7D%20%3D%20%5Comega_%7Bi%7D%5E%7B2%7D%20%2B%202~%5Calpha~%5Cdelta%20%5Ctheta)
Part(a):
Given,
,
and
. Substituting ll the values in the above equation, we have
![&& 2^{2} = 0.057^{2} + 2 \times 0.6 \times \delta \theta\\&or,& \delta \theta = \dfrac{4 - 0.057^{2}}{1.2} = 3.33~rad](https://tex.z-dn.net/?f=%26%26%202%5E%7B2%7D%20%3D%200.057%5E%7B2%7D%20%2B%202%20%5Ctimes%200.6%20%5Ctimes%20%5Cdelta%20%5Ctheta%5C%5C%26or%2C%26%20%5Cdelta%20%5Ctheta%20%3D%20%5Cdfrac%7B4%20-%200.057%5E%7B2%7D%7D%7B1.2%7D%20%3D%203.33~rad)
So the angle through which the parts rotates before reaching the final speed is
.
Part(b):
Given,
,
and
. So,
![&& (\omega_{f}^{new})^{2} = (\omega_{i}^{new})^{2} + 2~\alpha^{new} \delta \theta^{new}\\&or,& \delta \theta^{new} = \dfrac{( (\omega_{f}^{new})^{2} - (\omega_{i}^{new})^{2})}{2 \alpha}\\&or,& \delta \theta^{new} = \dfrac{4(\omega_{f}^{2} - \omega_{i}^{2})}{2~\alpha}\\&or,& \delta \theta^{new} = 2 \delta \theta](https://tex.z-dn.net/?f=%26%26%20%28%5Comega_%7Bf%7D%5E%7Bnew%7D%29%5E%7B2%7D%20%3D%20%28%5Comega_%7Bi%7D%5E%7Bnew%7D%29%5E%7B2%7D%20%2B%202~%5Calpha%5E%7Bnew%7D%20%5Cdelta%20%5Ctheta%5E%7Bnew%7D%5C%5C%26or%2C%26%20%5Cdelta%20%5Ctheta%5E%7Bnew%7D%20%3D%20%5Cdfrac%7B%28%20%28%5Comega_%7Bf%7D%5E%7Bnew%7D%29%5E%7B2%7D%20-%20%28%5Comega_%7Bi%7D%5E%7Bnew%7D%29%5E%7B2%7D%29%7D%7B2%20%5Calpha%7D%5C%5C%26or%2C%26%20%5Cdelta%20%5Ctheta%5E%7Bnew%7D%20%3D%20%5Cdfrac%7B4%28%5Comega_%7Bf%7D%5E%7B2%7D%20-%20%5Comega_%7Bi%7D%5E%7B2%7D%29%7D%7B2~%5Calpha%7D%5C%5C%26or%2C%26%20%5Cdelta%20%5Ctheta%5E%7Bnew%7D%20%3D%202%20%5Cdelta%20%5Ctheta)
Therefore, the angular displacement will be changes by a factor of 2.
Answer: C) bioluminescence
The middle layer of the world's ocean receives very little sunlight. This oceanic layer is called as twilight zone or diphotic zone or mesopelagic zone. This zone appears blue to black in color. The animals that live in this zone are adapted to survive in darkness, high pressure and cold water conditions.
The animals in this zone exhibit large eyes, which helps them to see in dark waters. Most animals are small, thin and dark which helps them to camouflage the predators in darkness. Some animals also possess large teeth and jaws. Many of these animals show bio luminescence, which means they can produce their own light. They have special organs which helps them to produce light by chemical reactions. Animals use light to find food and mates, they camouflage and distract the predators by light.
An open system is a system that has external interactions.
a closed system is a physical system that does not allow certain types of transfers in our out of the system.
an isolated system obeys the conservation law that its total energy- mass stays constant.