Answer:
Explanation:
We shall represent each displacement by vectors . i will represent east , -i west , j north and - j south .
Rhino walks 1.5 km west on day 1.
D₁ = - 1.5 i
The rhino then moves 0.7 km on a straight line in a direction of 15o east of north toward ground camera B
D₂ = .7 sin15 i + .7cos15 j
On the second day, the rhino moves 2.5 km directly south
D₃ = - 2.5 j
D = D₁ + D₂ + D₃
= - 1.5 i + .7 sin15 i + .7cos15 j - 2.5 j
= - 1.5 i + .181 i + .676 j - 2.5 j
= - 1.32 i - 1.824 j
magnitude of total displacement
= √ (1.32² +1.824²
= 2.25 km
For direction we shall calculate slope with x axis
Tanθ = - 1.824 / - 1.32
= 54°
So rhino will be towards 54° south of west as both x and y coordinates are negative.
Answer:
4. Both points have the same instantaneous angular velocity
Explanation:
Angular velocity is a measure of the the number of rotations per unit time. This does not depend on the radius of the wheel. Hence, all points on the wheel have the same angular velocity. This invalidates option 1.
The centripetal acceleration is given by the product to the square of the angular velocity and the radius or distance from the centre. A and B are located at different distances from the centre. Hence, they have different centripetal acceleration. This invalidates option 2.
The tangential acceleration depends on the linear velocity which itself is a product of the angular velocity and the distance from the centre. Hence, it is different for both points because they are at different distances from the centre.
Since both A and B are fixed points on the wheel, they move through equal angles in the same time. In fact, for any other fixed point, they all move through the same angle in the same time. This invalidates option 5.
Your answer would be the; <u>NET</u> force on the object. Refer to Newton's Laws of Forces and Motion.
Hope that helps!!!!!!!!!!!!!!!! : )
This is just testing your ability to recall that kinetic energy is given by:
<span>k.e. = ½mv² </span>
<span>where m is the mass and v is the velocity of the particle. </span>
<span>The frequency of the light is redundant information. </span>
<span>Here, you are given m = 9.1 * 10^-31 kg and v = 7.00 * 10^5 m/s. </span>
<span>Just plug in the values: </span>
<span>k.e. = ½ * 9.1 * 10^-31 * (7.00 * 10^5)² </span>
<span>k.e. = 2.23 * 10^-19 J
so it will be d:2.2*10^-19 J</span>
Answer:
Zero; no force is required to keep it going
Explanation:
Since the cannon ball is fired into frictionless space, there will be nothing to stop it, so it will keep going and going.
