A flat horizontal surface with an area of 518 cm^2 is inside a uniform electric field of 1.33 x 10^4 N/C. The angle between the
1 answer:
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The downward acceleration of the solid cylinder at the given tension in the string is determined as 2Tr/MR.
<h3>Downward acceleration of the cylinder</h3>
The downward acceleration of the solid cylinder is determined from the principle of conservation of angular momentum as shown below;
Iα = Tr
where;
- I is moment of inertia of the solid cylinder
- α is angular acceleration of the cylinder
- T is tension in the string
- r is length of the string
α = Tr/I
where;
- a is the downward acceleration of the solid cylinder
- R is radius of the cylinder
Thus, the downward acceleration of the solid cylinder at the given tension in the string is determined as 2Tr/MR.
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Answer:
Fundamental frequency is 200 Hz.
Explanation:
It is given that,
Frequency of the 3rd harmonic is 600 Hz.
Let f is the fundamental frequency. We need to find the value of f. The frequency of third harmonic is given by :
So, fundamental frequency f is equal to :
f = 200 Hz
So, the fundamental frequency of the harmonics is 200 Hz. Hence, this is the required solution.