2x-1≤x+5
2x≤x+6
x≤6
uhhh I hope that was easy to follow and it helped. anyways, just pretend the ≤ is a = and solve
It would be the same amount. So, 45 ml of NaOH is required to be added to the 45 ml of HCI to neutralize the acid fully. Here is a brief calculation:
Firstly, here is your formula: M(HCI) x V(HCI) = M(NaOh) x V(NaOH)
With the values put in: 0.35 x 45 = 0.35 x V(NaOH)
= 45 ml.
There is 45 ml of V(NaOH)
Let me know if you need anything else. :)
- Dotz
First one is a
the
second one is b
Si -Atomic number -14 -1s2 2s2 2p6 3s2 3p2 - 4 valence electrons
