Time taken = 3 hours
<h3>Further explanation</h3>
Given
speed : 75 mph
distance : 225 miles
Required
time taken
Solution
An equation of constant velocity motion

d = distance = m
v = speed = m / s
t = time = seconds
Input the value :
t = d : v
t = 225 miles : 75 miles/hour
t = 3 hours
Answer:
Magnesium chloride/Molar mass
95.211 g/mol
Explanation:
The mean kinetic energy per molecule is , where is the Boltzmann constant and T is the absolute temperature.
So at 1000°C, the T = 1273.15 K, kB=1.38 × 10-23, therefore the mean kinetic energy is 2.635 × 10⁻²⁰J.
<h3><u>
What is Kinetic energy ?</u></h3>
The energy an item has as a result of motion is known as kinetic energy.
A force must be applied to an item in order to accelerate it. We must put forth effort in order to apply a force. After the job is finished, energy is transferred to the item, which then moves at a new, constant speed. Kinetic energy is the type of energy that is transmitted and is dependent on the mass and speed attained.
Kinetic energy may be converted into other types of energy and transported between things. A flying squirrel may run into a chipmunk that is standing still, for instance. Some of the squirrel's original kinetic energy may have been transferred to the chipmunk or changed into another kind of energy after the impact.
To view more about kinetic energy, refer to;
brainly.com/question/2972267
#SPJ4
Answer:
D. The temperature of the the solution increases
Explanation:
Endothermic. Endo means in and thermic means a temperature, so Endothermic means the taking in of an temperature and the only answer choices that deal with temperature is,A and D. If it absorbs temperature it's going to rise.
For the answer to the question above asking w<span>hen an atom of n-14 is bombarded by an alpha particle, the single product is?
</span> <span>You're starting with 14/7 N, correct?
An alpha particle is two protons, two neutrons, which is 4/2, correct?
</span><span>So I</span> think the answer to your question is the third one which is <span>c. 18/9 f </span>