Answer:
130 g of sucrose
Explanation:
Boiling point elevation formula → ΔT = Kb . m
ΔT = Boiling T° solution - Boiling T° pure solvent → 0.39°C
0.39°C = 0.513°C/m . M
m = 0.760 mol/kg → molality = moles of solute / 1kg of solvent
Let's determine the moles of solute → molality . kg
0.760 mol/kg. 0.5 kg = 0.380 moles
If we convert the moles to mass, we'll get the answer
0.380 mol . 342.30 g/mol = 130g
Earth's atmosphere is 78% nitrogen, 21% oxygen, 0.9% argon, and 0.03% carbon dioxide with very small percentages of other elements. Our atmosphere also contains water vapor. In addition, Earth's atmosphere contains traces of dust particles, pollen, plant grains and other solid particles.
The chemical formula for the product is RbBr.
For the answer to the question above, use these formulas in solving your problem and as a guide.
<span>
MM = 342 (g/mol) </span>
<span>171 (g) / 342(g/mol) = x mol of sucrose </span>
<span>x moles of sucrose/ 1.25 L = Molarity of soultion
</span>I hope I helped you with your problem. Have a beautiful day!
