What is the volume of SO3 in 835 g SO3?

A balloon filled with 0.500 L of air at sea level is submerged in the water to a depth that produces a pressure of 3.25 atm. Wha

mario62 [17]

Answer:

Option a . 0.154L

Explanation:

P₁ . V₁ = P₂ . V₂

when we have constant temperature and constant moles for a certain gas.

At sea level, pressure is 1 atm so:

0.5 L . 1atm = V₂ . 3.25 atm

(0.5L . 1atm) / 3.25 atm = 0.154 L

6 0

3 years ago

Which solution is a buffer? which solution is a buffer? a solution that is 0.200 m in h2so4 and 0.200 m in na2so4 a solution tha

Ulleksa [173]

Buffer is formed from weak acid and its salt with strong base (its conjugate base)
So the only one correct answer is :
0.2 M H₃PO₄ and 0.2 M NaH₂PO₄
While all other choices are incorrect

4 0

3 years ago

Which values are written in proper scientific notation? Check all that apply. –350 –350.00 –3.50 × 104 0.000350 3.50 × 104 3.50

Oksanka [162]

-3.50 * 10^4
3.50 * 10^4
3.50 * 10^-4

7 0

3 years ago

Read 2 more answers

A gas with a volume of 15L at 640K is cooled at a constant pressure until the volume reaches 5L. What is the new temperature?

Brut [27]

Answer:

The new temperature is 213.33 K

Explanation:

Charles's law indicates that the volume of gas at constant pressure is directly proportional to its temperature. This law indicates that if the temperature increases the volume increases and if the temperature decreases the volume decreases.

So, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio between volume and temperature will always have the same value:

$\frac{V}{T}=k$

When you want to study two different states, an initial and a final one of a gas, the expression can be applied:

$\frac{V1}{T1} =\frac{V2}{T2}$

In this case, you know:

V1= 15 L
T1= 640 K
V2= 5 L
T2=?

Replacing:

$\frac{15 L}{640 K} =\frac{5 L}{T2}$

Solving:

$T2=\frac{5 L}{\frac{15 L}{640 K} }=\frac{5 L*640 K}{15 L}$

T2= 213.33 K

<u><em>The new temperature is 213.33 K</em></u>

8 0

3 years ago

What do you think happens to Difluoroethane at –24°C? Provide evidence to support your claim.

balandron [24]

Answer:

The following subsections explain the explanation according to the particular circumstance.

Explanation:

The boiling point seems to be the temperature beyond which the working fluid as well as the boiling phase would be at a predetermined pressure or voltage at equilibrium among one another and.
The vapor or boiling temperature of 1,1 difluoroethane seems to be -25oC at 1 atm, although as a gas it can remain at a higher temperature around -24oC.

6 0

3 years ago