All categories

2 years ago

What is the difference between glucose and fructose.

2 answers:

7 0

glucose breaks down disaccharides or polysaccharides with large sugar molecules and fructose is found in fruits and veggies like corn, mangos, and apples. they are both carbs.

CaHeK987 [17]2 years ago

4 0

Answer:

glucose is in large sugar molecules, while fructose is in simple fruits and vegetables

You might be interested in

Calculate the pH of a buffer solution created by reacting 100 mL of 0.1 M NH3 with 90 mL of 0.1 M HNO3. (Remember, you can find

algol13

This question is asking for the pH of a buffer solution between ammonia and nitric acid, with given volumes and concentrations. At the end, the result turns out to be 10.488.

<h3>Buffers</h3>

In chemistry, buffers are known as substances attempting to hold a relatively constant pH by mixing and acid and a base (weak and strong). In such a way, for the substances given, the first step will be to calculate the consumed moles as they are mixed:

$n_{NH_3}=0.1L*0.1mol/L=0.01mol\\\\n_{HNO_3}=0.09L*0.1mol/L=0.009mol$

Now, since ammonia is in a greater proportion, one can calculate how much of it is left after being consumed by the nitric acid:

$n_{NH_3}^{left}=0.01mol-0.009mol=0.001mol$

And its new concentration:

$[NH_3]=\frac{0.001mol}{0.1L+0.09L} =0.00526M$

Next, with ammonia's ionization:

$NH_3+H_2O\rightleftharpoons NH_4^++OH^-$

We set up the equilibrium expression based on ammonia's Kb:

$Kb=\frac{[NH_4^+][OH^-]}{[NH_3]}$

Which can be solved by introducing x and using ammonia's Kb:

$1.8x10^{-5}=\frac{x^2}{0.00526M}\\ \\$

Then, we solve for x which is also equal to the concentration of ammonium and hydroxide ions in the solution:

$x=\sqrt{0.00526*1.8x10^{-5}}=0.000308M$

Ultimately, we calculate the pOH and then turn it into pH with:

$pOH=-log(0.00308)=3.512\\\\pH=14-3.512=10.488$

Learn more about buffers: brainly.com/question/24188850

6 0

2 years ago

What do you use to find the actual amount of reactants

Rasek [7]

You need to use Stoichiometry

6 0

3 years ago

All mass of an atom is in the what

notka56 [123]

Answer:

Protons, neutrons, and electrons

Explanation:

Both protons and neutrons have a mass of 1 amu and are found in the nucleus. However, protons have a charge of +1, and neutrons are uncharged. Electrons have a mass of approximately 0 amu, orbit the nucleus, and have a charge of -1.

6 0

3 years ago

Sodium chloride can be produced from reacting sodium metal with chlorine gas. Carly reacts 2.6 g of sodium with 5.0 g of chlorin

Artemon [7]

Answer:

87.75%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2Na + Cl₂ —> 2NaCl

Next, we shall determine the masses of Na and Cl₂ that reacted and the mass of NaCl produced from the balanced equation. This can be obtained as follow:

Molar mass of Na = 23 g/mol

Mass of Na from the balanced equation = 2 × 23 = 46 g

Molar mass of Cl₂ = 2 × 35. 5 = 71 g/mol

Mass of Cl₂ from the balanced equation = 1 × 71 = 71 g

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

Mass of NaCl from the balanced equation = 2 × 58.5 = 117 g

Summary:

From the balanced equation above,

46 g of Na reacted with 71 g of Cl₂ to produce 117 g of NaCl.

Next, we shall determine the limiting reactant.

This can be obtained as follow:

From the balanced equation above,

46 g of Na reacted with 71 g of Cl₂.

Therefore, 2.6 g of Na will react with = (2.6 × 71)/46 = 4.01 g of Cl₂.

From the calculations made above, we can see that only 4.01 g of Cl₂ at of 5 g given in question reacted completely with 2.6 g of Na. Therefore, Na is the limiting reactant and Cl₂ is the excess reactant.

Next, we shall determine the theoretical yield of NaCl. The limiting reactant will be used to obtain the theoretical yield since all of it is consumed in the reaction.

The limiting reactant is Na and the theoretical yield of NaCl can be obtained as follow:

From the balanced equation above,

46 g of Na reacted to produce 117 g of NaCl.

Therefore, 2.6 g of Na will react to produce = (2.6 × 117)/46 = 6.61 g of NaCl.

Thus the theoretical yield of NaCl is 6.61 g

Finally, we shall determine the percentage yield of NaCl. This can be obtained as follow:

Actual yield of NaCl = 5.8 g

Theoretical yield of NaCl = 6.61 g

Percentage yield =?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 5.8/6.61 ×100

Percentage yield of NaCl = 87.75%

7 0

3 years ago

Use the information provided below to answer the

bixtya [17]

Answer:

208 g/mol and 87 g/mol

Explanation:

Number of protons = 82

Atomic mass = 126 + 82 = 208 g/mol

For ^{87}Sr

Number of neutrons = 49

Number of protons = 38

Atomic Mass = 49 + 38 = 87 g/mol

7 0

3 years ago