Answer:
a) i = -9.63 cm
, h ’= .0.24075 cm erect
b) i = 259.74 cm
,
Explanation:
For this exercise let's start by finding the focal length of the lens
1 / f = (n-1) (1 / R₁ - 1 / R₂)
1 / f = (1.70 -1)) 1 / ∞ - 1/13)
1 / f = 0.0538
f = - 18.57 cm
Now we can use the constructor equation
1 / f = 1 / o + 1 / i
1 / i = 1 / f - 1 / o
1 / i = -1 / 18.57 -1/20
1 / i = -0.1038 cm
I = -9.63 cm
For the height of the
image let's use magnification
m = h '/ h = - i / o
h ’= -h i / o
h ’= - 0.5 (-9.63) / 20
h ’= .0.24075 cm
b) we invert the lens
The focal length is
1 / f = (1.70 -1) (1/13 - 1 / int)
1 / f = 0.0538
f = 18.57 cm
1 / i = 1 / f -1 / o
1 / I = 1 / 18.57 - 1/20
1 / I = 3.85 10-3
i = 259.74 cm
h ’= - 0.5 259.74 / 20
h ’= 6.4935 cm
Answer:
The speed is 
Explanation:
From the question w are told that
The angle made is 
The distance above the surface of the water is 
The value of 
The maximum height attained by the fish is mathematically evaluate as
Making v which is the speed of the fish the subject of the formula
substituting values
![v = \sqrt{ \frac{2*10 *1.2 }{ [sin (30)]^2 } }](https://tex.z-dn.net/?f=v%20%3D%20%20%5Csqrt%7B%20%5Cfrac%7B2%2A10%20%2A1.2%20%7D%7B%20%5Bsin%20%2830%29%5D%5E2%20%20%7D%20%7D)
12. The answer would be C. 1.50 s. This is because if you divide 60 by 40, you will get 1.5.
13. For this one I'm not sure, but what I can tell you is that the heavier something is the faster it will sink, the lighter it is, it will float.
continents, paleoclimate indicators, truncated geologic features, and fossils:D
Answer:
Acceleration = 10.06 m/s²
Explanation:
1 mile = 1.6093km
1609.3m = 1 mile
1 m = 
mile
50.0 miles/hour = 
m/s
= 22.35m/s
from equation
S = Ut + 1/2 at²
v = U + at
22.35 = 0 + a * 2.22
a = 22.35 ÷ 2.22
= 10.06 m/s²
