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ahrayia [7]
2 years ago
8

How many moles are in 564 grams of copper

Chemistry
2 answers:
mojhsa [17]2 years ago
5 0

Answer:The answer is 63.546.

Explanation: The answer is 63.546. We assume you are converting between grams Copper and mole. You can view more details on each measurement unit: molecular weight of Copper or mol. The molecular formula for Copper is Cu. The SI base unit for amount of substance is the mole. 1 grams Copper is equal to 0.015736631731344 mole

tangare [24]2 years ago
5 0

Answer:

5.64 of copper

Explanation:

Given: 564 grams of copper

To find: in copper

Solution: If 1 grams Copper = 0.01 mole,

Then, 564 grams = multiply 564 and 0.01 mole

564 × 0.01 = 5.64

Therefore, there are 5.64 of copper in 564 grams

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When 91.5 g of isopropyl alcohol which has an empirical formula of C3H8O is burned in excess oxygen gas, how many grams of H2O a
Kobotan [32]

Answer:

109.7178g of H2O

Explanation:

First let us generate a balanced equation for the reaction. This is illustrated below:

2C3H8O + 9O2 —> 6CO2 + 8H2O

Next we will calculate the molar mass and masses of C3H8O and H20. This is illustrated below:

Molar Mass of C3H8O = (3x12.011) + (8x1.00794) + 15.9994 = 36.033 + 8.06352 + 15.9994 = 60.09592g/mol.

Mass of C3H8O from the balanced equation = 2 x 60.09592 = 120.19184g

Molar Mass of H2O = (2x1.00794) + 15.9994 = 2.01588 + 15.9994 = 18.01528g/mol

Mass of H2O from the balanced equation = 8 x 18.01528 = 144.12224g

From the equation,

120.19184g of C3H8O produced 144.12224g of H20.

Therefore, 91.5g of C3H8O will produce = (91.5 x 144.12224) /120.19184 = 109.7178g of H2O

7 0
3 years ago
How many moles of salt will you be using in this recipe?​
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6 0
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If the total mass of the products of a reaction is 90 gram, what was the total mass of the reactants
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3 years ago
which structures are found in eukaryotic cells a.chloroplast b. membrane bound organelles c. mitochondria d. nucleus e. pili
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4 0
3 years ago
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You need 270 ml of a 65% alcohol solution. on hand, you have a 90% alcohol mixture. how much of the 90% alcohol mixture and pure
olganol [36]

You must add 75 mL water to 195 mL 90 % alcohol to make 270 mL of 65 % alcohol.

<em>Step 1.</em> Calculate the volume of 90 % alcohol needed

You can use the dilution formula

<em>V</em>1×<em>C</em>1 = <em>V</em>2×<em>C</em>2

where

<em>V</em>1 and<em> V</em>2 are the volumes of the two solutions

<em>C</em>1 and <em>C</em>2 are the concentrations

You can solve the above formula to get

<em>V</em>2 = <em>V</em>1 × <em>C</em>1/<em>C</em>2

<em>V</em>1 = 270 mL; <em>C</em>1 = 65 %

V2 = ?; _____<em>C</em>2 = 90 %

∴<em>V</em>2 = 270 mL × (65 %/90 %) = 195 mL

You need 195 mL of 90 % alcohol to make 270 mL of 65 % RA

<em>Step 2</em>. Calculate the amount of water to add.

Volume of water = 270 mL – 195 mL = 75 mL

8 0
3 years ago
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