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Lana71 [14]
3 years ago
5

What is the density of a block marble that occupies 255 cm^3 and has a mass of 1000g

Chemistry
1 answer:
RUDIKE [14]3 years ago
4 0

Answer:

<h2>3.92 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question we have

density =  \frac{1000}{255}  \\  = 3.921568...

We have the final answer as

<h3>3.92 g/cm³</h3>

Hope this helps you

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According to the image, identify the number of neutrons in the most common isotope of aluminum.
wolverine [178]

Answer:

The number of neutron in the Aluminium Isotope is :

B. 14

Explanation:

Isotopes : These are the atoms which have same atomic number but have different mass number.

<u>This image shows the average atomic mass of Al element because it is in decimals</u>.

Atomic mass = 26.98154

(Note : mass number of single isotope can never be in decimals)

It is the average of mass of different isotopes of Al

Major Isotopes of _{13}^{26.98154}\textrm{Al} are :

  1. _{13}^{26}\textrm{Al}......atomic mass = 26
  2. _{13}^{27}\textrm{Al}.......atomic mass = 27

mass of Al given in image(26.98) is nearly equal to mass of 2nd isotope(27)

mass of _{13}^{26.98154}\textrm{Al}\ \approx 27

Now calculate the neutron in _{13}^{27}\textrm{Al}

Number of neutron = mass number - atomic number

                                = 27 - 13

Number of neutron = 14

(Atomic mass is same as mass number)

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2 years ago
Can you guess this place? In Arizona.
Temka [501]

Answer:

a high school classroom?

Explanation:

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8 0
2 years ago
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If your front lawn is 18.0 feet wide and 20.0 feet long. And each square foot of lawn accumulates 1450 new snow flakes every min
creativ13 [48]
To solve this problem, we begin by first calculating the area of the front lawn. The length and width of the lawn was given and the area of a rectangle is given by the formula: Area = length x width. Thus, the area of the front lawn can be obtained by multiplying 18 ft by 20 ft, wherein we get 360 ft^2 as the area. 

Second, the problem indicated that each square foot of lawn accumulates 1450 new snow flakes per minute. This can be translated into the expression 1450 snow flakes/ (minute·ft^2). In this way, we can convert it to units of mass (kg). Afterwards, we simply need to multiply it to the area of the lawn and convert minute to hour. The following expression is then used:

1450 snow flakes/ (minute·ft^2) x 1.90 mg/snow flake x 1 g/1000 mg x 1kg/1000 g x 360 ft^2 x 60 minutes/hour = 59.508 kg snow flake/hour

It is then calculated that 59.508 kg of snow flake accumulates in the lawn every hour. 
 
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3 years ago
I have several questions for Chemistry.
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8 0
3 years ago
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Which function allows a user to add another item to a list in Python? order() print() sort() append()
vovikov84 [41]

Answer:

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