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kaheart [24]
3 years ago
5

Which of the following best describes transverse waves?

Physics
2 answers:
gladu [14]3 years ago
7 0

Answer:

Displacement of particles is back and forth, perpendicular to the direction of wave motion.

den301095 [7]3 years ago
5 0

Best Answer: perpendicular to the direction of wave motion

think of you and a friend holding different ends of a rope. you shake your end side to side and the wave travels down to your friend's end. if you pay attention to a given segment of the rope, it moves, but it moves to the right and left while the wave travels forward. in a transverse wave, the constituents of the wave move perpendicular to the direction of motion of the wave itself.

a longitudinal wave, on the other hand, is the opposite. the constituents of the wave alternate moving in the same or opposite direction as the wave moves. this one is more like if you and your friend were holding onto a slinky. you give your end a push towards your friend, and you can see the wave move towards the other end.

hope that helps :D
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A storm cloud has an electric charge of (2.1400x10^1) C near the top of the cloud and (2.99x10^1) C near the bottom of the cloud
blagie [28]

Answer:

hey

Explanation:

4 0
3 years ago
A particle moves along the x axis. It is intially at the position 0.270 m, moving with velocity 0.140 m/s and acceleration -0.32
Nataliya [291]

Answer:

The position of the particle is -2.34 m.

Explanation:

Hi there!

The equation of position of a particle moving in a straight line with constant acceleration is the following:

x = x0 + v0 · t + 1/2 · a · t²

Where:

x = position of the particle at a time t:

x0 = initial position.

v0 = initial velocity.

t = time

a = acceleration

We have the following information:

x0 = 0.270 m

v0 = 0.140 m/s

a = -0.320 m/s²

t = 4.50 s  (In the question, where it says "4.50 m/s^2" it should say "4.50 s". I have looked on the web and have confirmed it).

Then, we have all the needed data to calculate the position of the particle:

x = x0 + v0 · t + 1/2 · a · t²

x = 0.270 m + 0.140 m/s · 4.50 s - 1/2 · 0.320 m/s² · (4.50 s)²

x = -2.34 m

The position of the particle is -2.34 m.

6 0
3 years ago
Please need help with this
Stella [2.4K]

Answer:

D. The objects particles move faster

4 0
3 years ago
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The rotational speed of earth is similar to?​
m_a_m_a [10]
Actually, the speed of the earth is the same everywhere, taking the angular speed as the valid measure of the speed
8 0
3 years ago
Melissa's favorite exercise equipment at the gym consists of various springs. in one exercise, she pulls a handle grip attached
konstantin123 [22]

The formula for force exerted on/by a spring is 

F = k*e where k is the spring constant and x is the distance stretched from unstrained position. This should allow you to find what you need.

 

Using F = k x e, 


where k is the spring constant, 


and e is the extension, 


The F is her weight = 45 X 0.80 


= 36 N

6 0
3 years ago
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