We balance the enthalpy absorbed by the steel and the enthalpy lost by wood. In this case, we use mCp ΔT to describe the problem. Cp (W) is 4 Cp(S). assuming the same mass, mCp(W) ΔT1 = <span>mCp(S) ΔT2 </span> 4* <span>ΔT1 = 40 </span><span>ΔT1 = 10. Hence the temperature of the wood is decreased by 10 degrees</span>