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Katen [24]
3 years ago
8

Wood has 4 times the heat capacity as steel. If I add the same amount of heat to the same amount of steel and wood, I find the t

emperature of the steel increases to 40°C. What is the temperature of the wood?
Physics
1 answer:
Y_Kistochka [10]3 years ago
5 0
We balance the enthalpy absorbed by the steel and the enthalpy lost by wood. In this case, we use mCp ΔT to describe the problem. Cp (W) is 4 Cp(S). assuming the same mass,
mCp(W) ΔT1 = <span>mCp(S) ΔT2
</span>  4* <span>ΔT1  = 40 
</span><span>ΔT1 = 10. Hence the temperature of the wood is decreased by 10 degrees</span>
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What is the momentum of a 1550kg car that is traveling 38.0 m/s?
konstantin123 [22]

Answer:

p = 58,900 kg m/s

Explanation:

p = m × v

p = 1,550 × 38.0

p = 58,900 kg m/s

5 0
3 years ago
Options are:<br>a)4Cn<br>b)5Cn<br>c)6 Cn<br>d)3 Cn<br>​
nasty-shy [4]

Answer:

Option B. 5 nC

Explanation:

From the question given above, the following data were obtained:

Capicitance (C) = 100 pF

Potential difference (V) = 50 V

Quantity of charge (Q) =?

Next, we shall convert 100 pF to Farad (F). This can be obtained as follow:

1 pF = 1×10¯¹² F

Therefore,

100 pF = 100 pF × 1×10¯¹² F / 1 pF

100 pF = 1×10¯¹⁰ F

Next, we shall determine the quantity of charge. This can be obtained as follow:

Capicitance (C) = 1×10¯¹⁰ F

Potential difference (V) = 50 V

Quantity of charge (Q) =?

Q = CV

Q = 1×10¯¹⁰ × 50

Q = 5×10¯⁹ C

Finally, we shall convert 5×10¯⁹ C to nano coulomb (nC). This can be obtained as follow:

1 C = 1×10⁹ nC

Therefore,

5×10¯⁹ C = 5×10¯⁹ C × 1×10⁹ nC / 1 C

5×10¯⁹ C = 5 nC

Thus, the quantity of charge is 5 nC

3 0
3 years ago
On a popular amusement park ride, the riders stand along the inside wall of a large cylinder with a diameter of 8.27 m. The cyli
____ [38]

Answer:

Explanation:

D = 8.27 m   ⇒  R = D / 2 = 8.27 m / 2 = 4.135 m

ω = 0.66 rev/sec = (0.66 rev/sec)*(2π rad/1 rev) = 4.1469 rad/s

We can apply the equation

Ff = W  ⇒  μ*N = m*g   <em>(I)</em>

then we have

N = Fc = m*ac = m*(ω²*R)

Returning to the equation <em>I</em>

<em />

μ*N = m*g    ⇒    μ*m*ω²*R = m*g   ⇒ μ = g / (ω²*R)

Finally

μ = (9.81 m/s²) / ((4.1469 rad/s)²*4.135 m) = 0.1379

3 0
3 years ago
A horse is trotting along pulling a sleigh through the snow. To move the 225 kg sleigh straight ahead at a constant speed, the h
RoseWind [281]

Answer:

a) The net force acting on the sleigh is zero because it is moving at a constant speed.

b) F_{fr}= \mu mg = F_{pull}, then \mu = \frac{F_{pull}}{mg} = 0.0557.

5 0
3 years ago
Your mom is making lunch which forces are acting on your mom
N76 [4]

The forces acting on your mom while cooking is Air resistance and the force of friction

<u>Explanation:</u>

<u>1. Air resistance:</u>

  • In simple words, Air resistance can be stated as the type of friction  between the air and the other materials.
  • In this scenario, there will be an air resistance and the air hits the mom while cooking via the doors or windows

<u>2. The force of friction:</u>

  • In simple words, friction can be stated as, the resistance that one surface or object encounters when moving over another.
  • While cooking the food mom would experience the friction since friction is the transfer of heat, and cooking is the process of receiving that heat.

7 0
4 years ago
Read 2 more answers
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