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Katen [24]
3 years ago
8

Wood has 4 times the heat capacity as steel. If I add the same amount of heat to the same amount of steel and wood, I find the t

emperature of the steel increases to 40°C. What is the temperature of the wood?
Physics
1 answer:
Y_Kistochka [10]3 years ago
5 0
We balance the enthalpy absorbed by the steel and the enthalpy lost by wood. In this case, we use mCp ΔT to describe the problem. Cp (W) is 4 Cp(S). assuming the same mass,
mCp(W) ΔT1 = <span>mCp(S) ΔT2
</span>  4* <span>ΔT1  = 40 
</span><span>ΔT1 = 10. Hence the temperature of the wood is decreased by 10 degrees</span>
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3 years ago
A speedboat is approaching a dock at 25 m/s (56 mph). When the dock is 150 m away, the driver begins to slow down. a) What accel
trasher [3.6K]

Answer:

a) -2.038 m/s²

b) 40.33 mph

c) 312.5 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-25^2}{2\times 150}\\\Rightarrow a=-2.083\ m/s^2

Acceleration of the boat is -2.083 m/s² if the boat will stop at 150 m.

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times -1\times 150+25^2}\\\Rightarrow v=18.03\ m/s

Speed of the boat by when it will hit the dock is 18.03 m/s

Converting to mph

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1\ h=3600\ seconds

18.03\times \frac{3600}{1609.34}=40.33\ mph

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v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-25^2}{2\times -1}\\\Rightarrow s=312.5\ m

The distance at which the boat will have to start decelerating is 312.5 m

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