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Katen [24]
3 years ago
8

Wood has 4 times the heat capacity as steel. If I add the same amount of heat to the same amount of steel and wood, I find the t

emperature of the steel increases to 40°C. What is the temperature of the wood?
Physics
1 answer:
Y_Kistochka [10]3 years ago
5 0
We balance the enthalpy absorbed by the steel and the enthalpy lost by wood. In this case, we use mCp ΔT to describe the problem. Cp (W) is 4 Cp(S). assuming the same mass,
mCp(W) ΔT1 = <span>mCp(S) ΔT2
</span>  4* <span>ΔT1  = 40 
</span><span>ΔT1 = 10. Hence the temperature of the wood is decreased by 10 degrees</span>
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Sunlight has its maximum intensity at a wavelength of 4.83 x 10'm; wha energy does this correspond to in e?
Lera25 [3.4K]

Answer:

E = 2,575 eV

Explanation:

For this exercise we will use the Planck equation and the relationship of the speed of light with the frequency and wavelength

     E = h f

     c = λ f

Where the Planck constant has a value of 6.63 10⁻³⁴ J s

Let's replace

    E = h c / λ

Let's calculate for wavelengths

    λ = 4.83 10-7 m     (blue)

    E = 6.63 10⁻³⁴ 3 10⁸ / 4.83 10⁻⁷

    E = 4.12 10-19 J

The transformation from J to eV is 1 eV = 1.6 10⁻¹⁹ J

    E = 4.12 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)

    E = 2,575 eV

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4 years ago
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A ball has a mass of 0.25 kg and is moving to the right at 1.0 m/s. It hits a ball of mass 0.15 kg that is initially at rest. Af
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0.55 m/s to the right is the answer.

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3 years ago
Three cars (car F, car G, and car H) are moving with the same speed and slam on their brakes. The most massive car is car F, and
Crazy boy [7]

To solve this problem it is necessary to apply the concepts related to Normal Force, frictional force, kinematic equations of motion and Newton's second law.

From the kinematic equations of motion we know that the relationship of acceleration, velocity and distance is given by

v_f^2=v_i^2+2ax

Where,

v_f = Final velocity

v_i = Initial Velocity

a = Acceleration

x = Displacement

Acceleration can be expressed in terms of the drag coefficient by means of

F_f = \mu_k (mg)  \rightarrowFrictional Force

F = ma \rightarrow Force by Newton's second Law

Where,

m = mass

a= acceleration

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g = Gravity

Equating both equation we have that

F_f = F

\mu_k mg=ma

a = \mu_k g

Therefore,

v_f^2=v_i^2+2ax

0=v_i^2+2(\mu_k g)x

Re-arrange to find x,

x = \frac{v_i^2}{2(-\mu_k g)}

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3 0
3 years ago
A rock has a mass of 25kg. The acceleration due to gravity is 10m/s and the height of the rock is 42 m. Find the potential energ
alisha [4.7K]

Answer:

 The potential energy of the rock = 10.5 kN

Explanation:

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 Potential energy, PE = mgh, where m is the mass, g is acceleration due to gravity and h is the height.

 PE = 25 x 10 x 42 = 10500 N = 10.5 kN

 The potential energy of the rock = 10.5 kN

7 0
3 years ago
Read 2 more answers
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