Digestive. This also includes the intestines.
Answer:

Explanation:
Given that:-
Mass of the hydrated salt = 7.028 g
Mass of the anhydrous salt = 3.100 g
Mass of water eliminated = Mass of the hydrated salt - Mass of the anhydrous salt = 7.028 - 3.100 g = 3.928 g
<u>Moles of water:
</u>
Mass of water = 3.928 g
Molar mass of
= 18 g/mol
The formula for the calculation of moles is shown below:
Thus, moles are:
<u>Moles of anhydrous salt:
</u>
Amount = 3.100 g
Molar mass of
= 142.04 g/mol
Thus, moles are:
The simplest ratio of the two are:
=0.02182 : 0.2212 = 1 : 10
<u>Hence, the formula for hydrate is:-
</u>
Answer:
There are three possible chemical equations for the combustion of sulfur:
- 2S (s) + O₂ (g) → 2SO (g)
- 2S (s) + 3O₂ (g) → 2SO₃ (g)
Explanation:
<em>Combustion</em> is a reaction with oxygen. The products of the reaction are oxides, and energy is released in the form of heat and light.
<em>Sulfur</em> iis a nonmetal, so the oxide formed is a nonmetal oxide.
The most common oxidation numbers of sulfur are -2, + 2, + 4, and + 6.
The combination of sulfur with oxygen may be only with the positive oxidation numbers (+2, + 4, and +6).
Then you have three different equations for sulfur combustion:
<u>1) Oxidation number +2:</u>
Which when balanced is: 2S(g) + O₂(g) → 2SO(g)
<u>2) Oxitation number +4:</u>
That equation is already balanced.
<u>3) Oxidation number +6:</u>
Which when balanced is: 2S(s) + 3O₂(g) → 2SO₃(g)