A gas mixture has 10% O2, 50% Ar (40 gmw) and 40% Pu (244 gmw). What is the density of this mixture?

Physics

1 answer:

Irina-Kira [14]3 years ago

3 0

Answer: 5.39g/L

Explanation:

We need to calculate the average molar mass of the mixture which will be:

= (10 × 32) + (50 × 40) + (40 × 244) / 100

= (320 + 2000 + 9760) / 100

= 12080 / 100

= 120.8g/mol

Since the volume occupied is 22.4L and 1 mole of the gas will occupies 22.4L given the standard temperature conditions, then the density of the mixture will be:

= Mass / volume

= 120.8 / 22.4

= 5.39g/L

Therefore, the density of the mixture will be 5.39g/L.

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