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nikklg [1K]
3 years ago
8

A gas mixture has 10% O2, 50% Ar (40 gmw) and 40% Pu (244 gmw). What is the density of this mixture?

Physics
1 answer:
Irina-Kira [14]3 years ago
3 0

Answer: 5.39g/L

Explanation:

We need to calculate the average molar mass of the mixture which will be:

= (10 × 32) + (50 × 40) + (40 × 244) / 100

= (320 + 2000 + 9760) / 100

= 12080 / 100

= 120.8g/mol

Since the volume occupied is 22.4L and 1 mole of the gas will occupies 22.4L given the standard temperature conditions, then the density of the mixture will be:

= Mass / volume

= 120.8 / 22.4

= 5.39g/L

Therefore, the density of the mixture will be 5.39g/L.

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Explanation:

a) Power consumption is 4100 J/min / 60 s/min = 68.3 W(atts)

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3 years ago
The apparent height of a building 10.5 km away is 0.02 radians. What is the approximate height of the building to the nearest me
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Answer:

Approximate height of the building is 23213 meters.

Explanation:

Let the height of the building be represented by h.

0.02 radians = 0.02 × \frac{180^{o} }{\pi }

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