An F-15 is flying straight and level lift equals weight) at 8 km standard day conditions at a velocity of 260 m/s. Given the fol
lowing data for the F-15, answer the questions that follow: Parasite/Profile drag coefficient CD0-0.018, wing span b-12.9 m, wing area s = 56.7 m2, mass m = 22.680 kg. Oswald efficiency factor eo0.915
(a) What is the wing's aspect ratio A?
(b) What is the lift force L generated by the aircraft?
(c) What is the aircraft's drag coefficient CD?
(d) What is the drag force D generated by the aircraft?
(a) What is the wing's aspect ratio A?
(b) What is the lift force L generated by the aircraft?
(c) What is the aircraft's drag coefficient CD?
(d) What is the drag force D generated by the aircraft?
1 answer:
You might be interested in
Answer:
Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.
Explanation:
Given that
Yield strength ,Sy= 240 MPa
Tensile strength = 310 MPa
Elastic modulus ,E= 110 GPa
L=380 mm
ΔL = 1.9 mm
Lets find strain:
Case 1 :
Strain due to elongation (testing)
ε = ΔL/L
ε = 1.9/380
ε = 0.005
Case 2 :
Strain due to yielding
ε '=0.0021
Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.
For computation of load strain due to testing should be less than the strain due to yielding.
Answer:
The magnitude of F1 is
The magnitude of F2 is
And the direction of F2 is
Explanation:
<u>Net Force </u>
Forces are represented as vectors since they have magnitude and direction. The diagram of forces is shown in the figure below.
The larger pull F1 is directed 21° west of north and is represented with the blue arrow. The other pull F2 is directed to an unspecified direction (red arrow). Since the resultant Ft (black arrow) is pointed North, the second force must be in the first quadrant. We must find out the magnitude and angle of this force.
Following the diagram, the sum of the vector components in the x-axis of F1 and F2 must be zero:
The sum of the vertical components of F1 and F2 must equal the total force Ft
Solving for in the first equation
The magnitude of F1 is
The magnitude of F2 is
And the direction of F2 is
