Kinetic energy is defined
KE = 1/2 * m * v^2
Let's put in the numbers
KE = 1/2 * 30 * 20^2 = 6000
Therefore, the answer is a) 6000 J
Answer:
0.572
Explanation:
First examine the force of friction at the slipping point where Ff = µsFN = µsmg.
the mass of the car is unknown,
The only force on the car that is not completely in the vertical direction is friction, so let us consider the sums of forces in the tangential and centerward directions.
First the tangential direction
∑Ft =Fft =mat
And then in the centerward direction ∑Fc =Ffc =mac =mv²t/r
Going back to our constant acceleration equations we see that v²t = v²ti +2at∆x = 2at πr/2
So going backwards and plugging in Ffc =m2atπr/ 2r =πmat
Ff = √(F2ft +F2fc)= matp √(1+π²)
µs = Ff /mg = at /g √(1+π²)=
1.70m/s/2 9.80 m/s² x√(1+π²)= 0.572
Answer:
Because unlike inert gas Noble gas sometimes indergo reaction
Explanation:
Inert gas as the name suggest means it can not undergoing reaction at most conditions.But as a science progresses it was found that some group 8 elements under special conditions of temperature and pressure can under go reaction this discovery led to why inert gas is not commonly used
Answer:
V = (v1 + v2) / 2 = (8 + 6.5) / 2 = 7.25 m/s average speed
t = 7.2 / 7.25 = .993 sec time to cross patch
a = (v2 - v1) / t = (6.5 - 8) / .993 = -1.51 m/s^2 or 1.5 m/s^2
change in momentum of car is given as
here we have
given that
m = 2000 kg
now we have