Explanation:
Missing Details. Most models can't incorporate all the details of complex natural phenomena.
Most Are Approximations. Most models include some approximations as a convenient way to describe something
<span>To find the kind of transformation that describes this change from d(v) = 0.045v2 to d(v) = 0.039v2, find the relation between the two functions:
0.045/.039 = 45/39 = 15/13
The you have to multiply the first function times 13/15 to transform it to the second function.
When you multiply by a factor less than one you are compressiong the function vertically (if you multiply by a factor greater than 1 you are stretching vertically).
On the other hand, that the distance to stop the minimum braking distance will be smaller with the second function.
Then, the answer is that the transformation is a vertical compression by a factor of 13/15 and the braking distance will be less with optimum new tires than with tires having more wear.
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Answer:
a = 0.154 [m/s^2]
Explanation:
To solve this problem we must use the following formula of kinematics.
where:
Vf = final velocity = 0
Vi = initial velocity = 100 [km/h]
t = time = 3 [min] = 180 [s]
Now we need to convert the velocity from [km/h] to [m/s]
![100[\frac{km}{h} ]*1000[\frac{m}{1km} ]*1[\frac{h}{3600s} ]=27.77[\frac{m}{s} ]](https://tex.z-dn.net/?f=100%5B%5Cfrac%7Bkm%7D%7Bh%7D%20%5D%2A1000%5B%5Cfrac%7Bm%7D%7B1km%7D%20%5D%2A1%5B%5Cfrac%7Bh%7D%7B3600s%7D%20%5D%3D27.77%5B%5Cfrac%7Bm%7D%7Bs%7D%20%5D)
0 = 27.77 - (a*180)
a = 0.154 [m/s^2]
Note: the negative sign of the equation shows, that the car slows down until it stops
Answer:
The object exerts <em>same</em> amount of force in elastic and inelastic collisions.
Explanation:
The force an object exerts is not different between the two types of collisions. What changes from elastic to inelastic is the amount of energy transformed from kinetic to other type during an inelastic collision.
If wave exhibits reinforcement, the component waves must be in phase with each other. Components waves combine to form a resultant with the same wavelength but the amplitude which is greater than the amplitude of either of the individual component waves, and this happens in constructive interference.
In phase the features of the two waves they completely match at zero degrees.
