Question

If a fisherman applies a horizontal force with magnitude 47.0 NN to the box and produces an acceleration of magnitude 3.20 m/s2m/s2, what is the mass of the box

Answer 1

Answer:

The correct solution is "14.6875 kg".

Explanation:

Given values:

Force,

F = 47.0 N

Acceleration,

a = 3.20 m/s²

Now,

⇒ $Force=Mass\times Acceleration$

or,

⇒       $F=ma$

⇒    $47.0=m\times 3.20$

⇒       $m=\frac{47.0}{3.20}$

⇒           $=14.6875 \ kg$