Question

A flea jumps straight up to a maximum height of 0.440 m . what is its initial velocity v0 as it leaves the ground?'

Answer 1

Initial velocity = $\(v_0\)$

acceleration in the downward direction = -9.8 $\(\frac {m}{s^2}\)$

Final velocity at the highest point = 0

Maximum height reached = 0.440 m

Now, Using third equation of motion:

$\(v^2 = {v_0}^{2} + 2aH$

$\(0^2 = {v_0}^{2} - 2 \times 9.8 \times 0.440$

$\({v_0}^{2} = 2 \times 9.8 \times 0.440\)$

$\(v_0 = 2.936 \frac {m}{s}\)$

Velocity with which the flea jumps = $\(2.936 \frac {m}{s}\)$