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docker41 [41]
4 years ago
10

How far is the Earth from the Sun?

Physics
2 answers:
a_sh-v [17]4 years ago
6 0

Answer:

93.531 million miles away❣️

Explanation:

ohaa [14]4 years ago
4 0

Answer:93.431 million mi

Explanation:

google lol

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An object with mass 1.2 kg is moving at a constant speed in a circle with radius 2.5 m. If the
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3.9m/s² is the acceleration

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3 years ago
100 points please help
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The first picture is B The second picture electric current is the 1st one Voltage is the last one so that leaves resistance the middle picture. The last picture is A

Explanation:

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2 years ago
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1. Calculate the work done by a 47 N force pushing a pencil 0.26 m.<br> 47x .26 = 12J<br> Solve it
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I need help with one to

Explanation:

Im trying to ask someone but no one knows :(

7 0
3 years ago
Even in the most advanced circuits, we cannot oscillate electrons back and forth at that rate through wires. But we can oscillat
den301095 [7]

Answer:

the oscillations of the electrons must be in the 10⁸ Hz = 100 MHz range

Explanation:

The speed of a wave of radio, television, light, heat, all are manifestations of electromagnetic waves that are oscillations of electric and magnetic fields that support each other, the speed of all these waves is the same and the vacuum is equal to c = 3 108 m / s

All waves have a relationship between the speed of the wave, its frequency and wavelength

          c = λ f

          f = c /λ

for this case lam = 1 m

          f = 3 10⁸/1

          f = 3 10⁸ Hz

the oscillations of the electrons must be in the MHz range

It should be clarified that the speed of light in air is a little lower

          n = c / v

          v = c / n

the refractive index of vacuum is n = 1 and the refractive index of air is n = 1.000002

5 0
3 years ago
A projectile is fired upward at an angle θ above the horizontal with an initial speed v0. At its maximum height, what are its ve
aliya0001 [1]

Answer:

\vec{v}_{\rm max} = v\cos(\theta)(\^x)\\|\vec{v}_{\rm max}| = v\cos(\theta)\\\vec{a} = \vec{g} = -9.8\^y

Explanation:

The equations of kinematics will be used to solve this question:

y - y_0 = v_{y_0}t + \frac{1}{2}a_yt^2\\v_y^2 = v_{y_0}^2 + 2a_y(y - y_0)\\v_y = v_{y_0} + a_yt

At its maximum height, the projectile has zero velocity in the y-direction. But its velocity in the x-direction is unaffected.

First, let's apply the above equations to the x-direction.

There is no acceleration in the x-direction. So, its velocity in the x-direction is constant during the motion.

v_x = v_{x_0} + a_xt = v_{x_0} + 0\\v_x = v_{x_0} = v\cos(\theta)

Therefore, the velocity vector of the projectile is

v_{max} = v_x = v\cos(\theta)

The speed of the projectile is the same.

The acceleration vector is constant during the motion and equal to the gravitational acceleration, which is -9.8 downwards.

7 0
4 years ago
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