Which of the following is an example of an indirect observation?

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Igoryamba

Answer:

b

Explanation:

7 0

3 years ago

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Define electric potential energy

Verizon [17]

Electric potential energy, or Electrostatic potential energy, is a potential energy that results from conservative Coulomb forces and is associated with the configuration of a particular set of point charges within a defined system.

3 0

3 years ago

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An Atwood machine consists of two masses, mA = 6.8 kg and mB = 8.0 kg , connected by a cord that passes over a pulley free to ro

Lisa [10]

To solve this problem it is necessary to apply the concewptos related to Torque, kinetic movement and Newton's second Law.

By definition Newton's second law is described as

F= ma

Where,

m= mass

a = Acceleration

Part A) According to the information (and as can be seen in the attached graph) a sum of forces is carried out in mass B, it is obtained that,

$\sum F = m_b a$

$m_Bg-T_B = m_Ba$

$T_B = m_Bg-m_Ba$

In the case of mass A,

$\sum F = m_A a$

$T_A = m_Ag-m_Aa$

Making summation of Torques in the Pulley we have to

$\sum\tau = I\alpha$

$T_BR_0-T_AR_0=I\alpha$

$T_B-T_A=I\frac{a}{R^2_0}$

Replacing the values previously found,

$(m_Bg-m_Ba )-(m_Ag-m_Aa )=I\frac{a}{R^2_0}$

$(m_B-m_A)g-(m_B+m_A)a=I\frac{a}{R^2_0}$

$a = \frac{(m_B-m_A)g}{\frac{I}{R_0^2}+(m_B+m_A)}$

$a = \frac{(m_B-m_A)g}{\frac{MR^2_0^2/2}{R_0^2}+(m_B+m_A)}$

$a =\frac{(m_B-m_A)g}{\frac{M}{2}+(m_B+m_A)}$

Replacing with our values

$a =\frac{(8-6.8)(9.8)}{\frac{0.8}{2}+(8+6.8)}$

$a=0.7736m/s^2$

PART B) Ignoring the moment of inertia the acceleration would be given by

$a' =\frac{(m_B-m_A)g}{(m_B+m_A)}$

$a' =\frac{(8-6.8)(9.8)}{(8+6.8)}$

$a' = 0.7945$

Therefore the error would be,

$\%error = \frac{a'-a}{a}*100$

$\%error = \frac{0.7945-0.7736}{0.7736}*100$

$\%error = 2.7%$

8 0

3 years ago

At what speed must a 0.6 kg stone be thrown in order that it has a relativistic mass of 0.76 kg? (c = 3.00 x 10^8 m/s) (A) 0.39

exis [7]

Explanation:

It is given that,

Relativistic Mass of the stone, m₀ = 0.6

Mass, $m=0.76\ kg$

Relativistic mass is given by :

$m=\dfrac{m_o}{\sqrt{1-\dfrac{v^2}{c^2}}}$ .........(1)

Where

c is the speed of light

On rearranging equation (1) we get :

$v^2=c^2(1-(\dfrac{m_o}{m})^2)$

$v=c\sqrt{ (1-(\dfrac{m_o}{m})^2)}$

$v=c\sqrt{ (1-(\dfrac{0.6}{0.76})^2)}$

v = 0.61378 c

or

v = 0.6138 c

So, the correct option is (c). Hence, this is the required solution.

8 0

3 years ago

How to find out the heat capacity of a material?

DochEvi [55]

$\huge\underline{\underline{\boxed{\mathbb {EXPLANATION}}}}$

The heat capacity is given by the expression:

$\longrightarrow \sf{\triangle Q= m \triangle C \triangle T}$

$\longrightarrow \sf{Q= \: Heat}$

$\longrightarrow \sf{M= \: Mass}$

$\longrightarrow \sf{C= \: Specific \: Heat}$

$\longrightarrow \sf{T= \: Temperature}$

$\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}$

$\leadsto$ When the $\bm{heat}$ is measured in the calorimeter, we obtain a value, and since we know the mass of the material and we control the change in $\bm{temperature}$ , we can then determine the specific heat "C" by simply remplazing in the expression.

5 0

2 years ago