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2 years ago

Which star has the highest surface temperature?

Physics

2 answers:

barxatty [35]2 years ago

8 0

Answer:white star

Explanation:

lesya [120]2 years ago

7 0

Answer:

white star

Explanation:

because it is the hottest form of a star

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What clouds are best associated with thunderstorms?

Oliga [24]

Answer:

Cumulus Congestus & Cumulonimbus Clouds

6 0

3 years ago

A long solenoid has a diameter of 11.1 cm. When a current i exists in its windings, a uniform magnetic field of magnitude B = 42

Pepsi [2]

Answer:

$E(1) = 1.44\times 10^{-4} v/m$

$E(2) = 1.34\times 10^{-4} v/m$

Explanation:

Given data:

diameter of solenoid is 11.1 cm

B = 42.9 mT

dR = 6.65 mT/s

d(1) = 4.34 cm

d(2) = 7.46 cm

we know that

electric field due to solenoid is given as

E = 1/2 dB/dt (r)

$E(1)= \frac{0.0434}{2} \times (6.65\times 10^{-3})$

$E(1) = 1.44\times 10^{-4} v/m$

E = 1/2 dB/dt (R^2)/r

$E(2)= \frac{0.055^2}{2\times 0.0746} \times (6.65\times 10^{-3})$

$E(2) = 1.34\times 10^{-4} v/m$

6 0

2 years ago

A painter on a ladder, painting the ceiling of a room comments. “It is hotter up here by the ceiling than it is down on the floo

ira [324]

Answer:

1. Hot air is less dense and has moved upward allowing cool air to move downward which is less dens

(Convection current)

2. The ceiling has transferred heat to him by radiation.

Explanation:

During the day when air is heated as a result of the ceiling transferring heat to it, it becomes less dens and it gains energy, which make it lighter in weight than cooler air, this hot air moves upward allowing cooler air to move downward.

4 0

3 years ago

A spring has a natural length of 0.5 m and was stretched by 0.02 m. if the spring had a resultant energy of 0.5 j what is the sp

Anna71 [15]

$\textbf{2500 }\dfrac{\textbf{kg}}{\textbf{s}^{\textbf{2}}}$

Explanation:

Natural length of a spring is $0.5\text{ }m$ . The spring is streched by $0.02\text{ }m$ . The resultant energy of the spring is $0.5\text{ }J$ .

The potential energy of an ideal spring with spring constant $k$ and elongation $x$ is given by $\dfrac{1}{2}kx^{2}$ .

So, in the current problem, the natural length of the spring is not required to find the spring constant $k$ .

$\text{Potential Energy in the spring = }\dfrac{1}{2}kx^{2}\\0.5\text{ }J\text{ }=\text{ }\dfrac{1}{2}k(0.02\text{ }m)^{2}\\k\times0.0004\text{ }m^{2}\text{ }=\text{ }1\text{ }J\text{ }=\text{ }1\text{ }kg\frac{m^{2}}{s^{2}}\\k\text{ }=\text{ }\dfrac{1\text{ }kg\dfrac{m^{2}}{s^{2}}}{0.0004\text{ }m^{2}}\text{ }=\text{ }2500\text{ }\frac{kg}{s^{2}}$

∴ The spring constant of the spring = $2500\text{ }\frac{kg}{s^{2}}$

4 0

3 years ago

A bowling ball with a mass of 7.0 kg, generates 56.0 kgᐧm/s units of momentum. What

Misha Larkins [42]

Answer:

8 m/s

Explanation:

$p = mv \\ 56 = (7.0)(v) \\ v = 8.0 \: m {s}^{ - 1}$

7 0

2 years ago