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Fiesta28 [93]
3 years ago
9

Substances that prevent certain chemical reactions are called ___.

Physics
1 answer:
yuradex [85]3 years ago
5 0

Substances that prevent or reduce the rate of a chemical reaction are called as inhibitors.

<u>Explanation:</u>

Inhibitors are those substances that either prevent or reduce the rate of a chemical reaction. Ex: Acetanilide slows down the decomposition of hydrogen peroxide solution.  

Inhibitors even reduce the effectiveness of catalysts without hindering their composition. There are primarily two kinds of inhibitors- reversible and irreversible. Where, reversible inhibitors slows the rate of any reaction, irreversible inhibitors completely prevents the unwanted reactions.

Where catalysts are used to increase the rate of a reaction, inhibitors stand as a wall for the unwanted reactions to occur. For example, in case of silver tarnishing, to prevent silver jewellery being tarnished, a thin layer of rhodium is applied on it which works like an inhibitor for formation reaction of silver sulphides (the tarnish).

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At what speed do a bicycle and its rider, with a combined mass of 100 kg, have the same momentum as a 1400 kg car traveling at 6
Ilia_Sergeevich [38]
Momentum of car

Given: Mass m= 1,400 Kg;    V = 6.0 m/s

Formula:  P = mv    

                P = (1,400 Kg)(6.0 m/s)

                P = 8,400 Kg.m/s

Velocity of the rider to have the same momentum as a car.

Mass of rider and bicycle  m = 100 Kg

P = mv

V = P/m

V = 8,400 Kg.m/s/100 Kg

V = 84 m/s









7 0
2 years ago
1. Calculate the height of tree, 250 m away that produces
gtnhenbr [62]

Answer:

Explanation:

1.5/30 = x/250

x = 12.5 m

5 0
2 years ago
You are caulking a window. The caulk is rather thick and, to lay the bead correctly, the exit nozzle is small. A caulking gun us
ZanzabumX [31]

Answer:

The answer is

A. Pressure is distributed uniformly throughout the fluid and the area of the plunger is much larger than the area of the opening.

Explanation:

 The question is incomplete, here is a complete question with full options

You are caulking a window. The caulk is rather thick and, to lay the bead correctly, the exit nozzle is small. A caulking gun uses a plunger which is operated by pulling back on a handle. You must squeeze the handle very hard to get the caulk to come out of the narrow opening because:_________.

A. pressure is distributed uniformly throughout the fluid and the area of the plunger is much larger than the area of the opening.

B. viscous drag between the walls of the tip and the caulk causes the caulk to swirl around chaotically.

C. Newton’s third law requires most of the energy in the caulk to be used to push back on the plunger rather than moving it through the tip.

D. the high density of the caulk impedes its flow through the small opening.

Since the caulk is thick and the exit nozzle is small, the pressure needed to deliver the caulk will be very high as pressure is uniformly distributed at the plunger side at every part of the caulk, hence very high pressure is needed to deliver the caulk which is why the handle needed the very hard squeeze

3 0
3 years ago
Say that you are in a large room at temperature TC = 300 K. Someone gives you a pot of hot soup at a temperature of TH = 340 K.
DiKsa [7]

Answer:0.061

Explanation:

Given

T_C=300 k

Temperature of soup T_H=340 K

heat capacity of soup c_v=33 J/K

Here Temperature of soup is constantly decreasing

suppose T is the temperature of soup at any  instant

efficiency is given by

\eta =\frac{dW}{Q}=1-\frac{T_C}{T}

dW=Q(1-\frac{T_C}{T})

dW=c_v(1-\frac{T_C}{T})dT

integrating From T_H to T_C

\int dW=\int_{T_C}^{T_H}c_v(1-\frac{T_C}{T})dT

W=\int_{T_C}^{T_H}33\cdot (1-\frac{300}{T})dT

W=c_v\left [ T-T_C\ln T\right ]_{T_H}^{T_C}

W=c_v\left [ \left ( T_C-T_H\right )-T_C\left ( \ln \frac{T_C}{T_H}\right )\right ]

Now heat lost by soup is given by

Q=c_v(T_C-T_H)

Fraction of the total heat that is lost by the soup can be turned is given by

=\frac{W}{Q}

=\frac{c_v\left [ \left ( T_C-T_H\right )-T_C\left ( \ln \frac{T_C}{T_H}\right )\right ]}{c_v(T_C-T_H)}

=\frac{T_C-T_H-T_C\ln (\frac{T_C}{T_H})}{T_C-T_H}

=\frac{300-340-300\ln (\frac{300}{340})}{300-340}

=\frac{-40+37.548}{-40}

=0.061

4 0
3 years ago
I need help quick pls . Its either physical or chemical change !
Trava [24]
Physical, chemical, chemical, physical, I’m pretty sure. Natural things, like you starting to breathe heavier are physical most of the time!!!
8 0
3 years ago
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