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3 years ago

A tennis player hit a .057-kg ball with a force of 40 N. The duration of the force was .05 s.

Physics

1 answer:

asambeis [7]3 years ago

8 0

40 because it is the highest and also because

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How much work is done by 0.070 m3 of gas, when the volume remains constant with pressure of 63 x 105 Pa?

ICE Princess25 [194]

Answer:

W = 0 J

Explanation:

The amount of work done by gas at constant pressure is given by the following formula:

$W = P\Delta V$

where,

W = Work done by the gas

P = Pressure of the gas

ΔV = Change in the volume of the gas

Since the volume of the gas is constant. Therefore, there is no change in the volume of the gas:

$W = P(0\ m^3)\\$

W = 0 J

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2 years ago

A skier accelerates down the hill at 3m/s2 how fast is he going in 4 seconds

almond37 [142]

Answer:

Explanation: simple kinematics

we suppose that initially vo= 0 so if the skier moves 4s :

vf = vo +at = 0 + 3*4 = 12 m/s

best wishes from colombia

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3 years ago

A uniform plank of mass 10kg and length 10m rests on two supports, A and B as shown. A boy of weight 500N stands at a distance o

kifflom [539]

Answer:

U² = 142.86 N

U¹ = 357.14 N

Explanation:

Taking summation of the moment about point A, we get the following equilibrium equation: (taking clockwise direction as positive)

$W(2\ m) - U^2(7\ m) = 0$

where,

W = weight of boy = 500 N

U² = reaction ay B = ?

Therefore,

$(500\ N)(2\ m)-(U^2)(7\ m)=0\\U^2=\frac{1000\ Nm}{7\ m}\\$

U² = 142.86 N

Now, taking summation of forces on the plank. Taking upward direction as positive, for equilibrium position:

$W-U^1-U^2=0\\500\ N - 142.86\ N = U^1\\$

U¹ = 357.14 N

3 0

2 years ago

Of the following systems, which contains the most heat?

densk [106]

Answer:d

Explanation:

Given systems are state of matter and do not contain any heat instead Heat is required to change Phase or raise the temperature of the particular system.

For example 600 kg of ice at $0^{\circ}C$

Heat Required to convert it to water at $0^{\circ}C$ is

$Q=m\times L$

Where L=latent heat of Fusion $=334 J/gm$

$Q=600\times 334\times 1000$

$Q=200.4 MJ$

8 0

3 years ago

a sealed cylinder contains a sample of ideal gas at a pressure of 2.0 atm. The rms speed of the molecules is v0. If the rms spee

fredd [130]

Answer:

P_2 = 1.62 atm

Explanation:

We know the formula for the rms speed of the ideal gas is given by

$v_{rsm}=\sqrt{\frac{3PV}{m} }$

P= pressure of the surrounding

V= volume of the vessel

m= mass of the gas

Now, From this formula rms speed (v_rms) is directly proportional to square root is pressure.

Then

$\frac{v_{rsm,1}}{v_{rsm,2}} =\sqrt{\frac{P_1}{P_2} }$

given that v_rsm,1= v0

and v_rsm,2=0.9v0

putting these values we get

$\frac{v0}{0.9v0} =\sqrt{\frac{2}{P_2} }$

P_2 = 1.62 atm

8 0

3 years ago

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