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Aleksandr [31]
3 years ago
12

A tennis player hit a .057-kg ball with a force of 40 N. The duration of the force was .05 s.

Physics
1 answer:
asambeis [7]3 years ago
8 0
40 because it is the highest and also because
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**HELP ASAP**
Tcecarenko [31]
The answer of this question is B.
5 0
3 years ago
In the high jump, the kinetic energy of an athlete is transformed into gravitational potential energy without the aid of a pole.
Fiesta28 [93]

Answer:

6.0 m/s

Explanation:

According to the law of conservation of energy, the total mechanical energy (potential, PE, + kinetic, KE) of the athlete must be conserved.

Therefore, we can write:

KE_i+PE_i =KE_f+PE_f

or

\frac{1}{2}mu^2+0=\frac{1}{2}mv^2+mgh

where:

m is the mass of the athlete

u is the initial speed of the athlete (at the bottom)

0 is the initial potential energy of the athlete (at the bottom)

v = 0.80 m/s is the final speed of the athlete (at the top)

g=9.8 m/s^2 is the acceleration due to gravity

h = 1.80 m is the final height of the athlete (at the top)

Solving the equation for u, we find the initial speed at which the athlete must jump:

u=\sqrt{v^2+2gh}=\sqrt{0.80^2+2(9.8)(1.80)}=6.0 m/s

4 0
3 years ago
The acceleration of the car with the data in the table above would be
neonofarm [45]

The acceleration of the car would be 0.33 first and then it would be 0.17.

<u>Explanation:</u>

An applied force is a force that is applied to an object by an individual or another item. On the off chance that an individual is pushing a work area over the room, at that point there is an applied power following up on the article. The applied power is the power applied on the work area by the individual.

The net force applied to the object rises to the mass of the article increased by the measure of its acceleration. The net power following up on the soccer ball is equivalent to the mass of the soccer ball duplicated by its adjustment in speed each second (its acceleration).

6 0
3 years ago
A 300-n force acts on a 25-kg object. the acceleration of the object is?
Over [174]
To solve the answer use the equation: a = fnet / m

a = 300 N / 25 kg

300 N / 25 kg = 12m/s

The acceleration of the object is 12m/s

8 0
3 years ago
Read 2 more answers
Two boxes (24 kg and 62 kg) are being pushed across a horizontal frictionless surface, as the drawing shows. The 36-N pushing fo
defon

Answer:

F = 26.04 N

Explanation:

As we know that system of two boxes are moving on frictionless surface

So here if two boxes are considered as a system

then we have

F = (m_1 + m_2) a

m_1 = 24 kg

m_2 = 62 kg

F = 36 N

36 = (24 + 62) a

a = 0.42 m/s^2

Now since we know that both the boxes are moving together so force applied by first box on other box is given as

F = ma

F = (62 \times 0.42)

F = 26.04 N

6 0
3 years ago
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