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miv72 [106K]
3 years ago
9

Alex throws a 0.15-kg rubber ball down onto the floor. The ball’s speed just before impact is 6.5 m/s and just after is 3.5 m/s.

If the ball is in contact with the floor for 0.050 s, what is the magnitude of the average force applied by the floor on the ball?
Physics
1 answer:
Morgarella [4.7K]3 years ago
6 0

Answer:

F = 30 N  Directed up

Explanation:

We can solve this problem using the momentum and momentum relationship.

      I = ΔP

     I = ∫ F dt

As we are asked for the average force, that leaves the integral, giving

    I = F t

    F t = m v_{f} - m v₀

    F = m (v_{f}-v₀) / t

Note that, if you define the upward positive direction, the initial velocity is negative

Let's calculate

     F = 0.15 (3.5 - (-6.5)) / 0.050

     F = 30 N

Directed up

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Compare the collision between two baseballs and a catcher's mitt.
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The applied force is different for the two cases

The case A with a greater force involves the greatest momentum change

The case A involves the greatest force.

<h3>What is collision?</h3>
  • This is the head-on impact between two object moving in opposite or same direction.

The initial momentum of the two ball is the same.

P = mv

where;

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Since the force applied by the arm is different, the final velocity of the balls before stopping will be different.

Thus, the final momentum of each ball will be different

The impulse experienced by each ball is different since impulse is the change in momentum of the balls.

J = ΔP

The force applied by the rigid arm is greater than the force applied by the relaxed arm because the force applied by the rigid arm will cause the ball to be brought to rest faster.

Thus, we can conclude the following;

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Learn more about impulse here: brainly.com/question/25700778

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HELP ASAP!!! The gravitational pull of the Moon is much less than the
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I'm pretty sure its B and C

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7 0
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The increase in potential energy of his mother if her mass is 56.0 kg will be 6031.97 J.

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The energy that an item has due to its location in a gravitational field is known as gravitational potential energy.

The potential energy increases by 3773 J

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(h₂-h₁) = 10.98

Case 2 ;

ΔPE =?

ΔPE=mg(h₂-h₁)

ΔPE=56.0 × 9.81 ×10.98

ΔPE=6031.97 J.

Hence, the increase in potential energy of his mother if her mass is 56.0 kg will be 6031.97 J.

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brainly.com/question/3884855#SPJ1

#SPJ1

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Answer:

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