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3 years ago

The entropy of a sample of CO2 increases as the CO2 changes from

2 answers:

8 0

The answer is (4) solid to gas. The entropy is the measurement of disorder. The entropy of CO2 under different status will increase from solid to liquid to gas. So the answer is (4).

alex41 [277]3 years ago

5 0

Answer: Option (4) is the correct answer.

Explanation:

Entropy is defined as the degree of randomness. That is, when particles of an object or matter are rapidly moving from one place to another then it means that the object has high entropy.

For example, gases have high entropy than liquids and solids.

Whereas when particles of an object are closer to each other then it means that entropy of the object is low. For example, solids have low entropy.

Thus, we can conclude that the entropy of a sample of $CO_{2}$ increases as the $CO_{2}$ changes from solid to gas.

You might be interested in

The following is an example of what type of chemical reaction?

Svetlanka [38]

This is a D. combustion reaction

That is because you add O2 which is necessary for a combustion, while the results are CO2 and water. What you are missing is a ---> after the 2O2 (g)

4 0

3 years ago

Draw a lewis structure for ketene, c2h2o, which has a carbon–carbon double bond

MrMuchimi

Visual representation of covalent bonding indicating the valence shell electrons in the molecule, lines represents the shared pair of electron and pair of electrons that are not involved in bonding are represented as dots(lone pairs) are known as Lewis structures.

Compound formation takes place in order to complete the octet of each element that is according to octet rule, each atom forms bond with other atom in order to complete their octet that is to get eight electrons in its valence shell and attain stability.

An organic compound of the form $R^{'}R^{''}C=C=O$ is known as ketene.

The given ketene is $C_2H_2O$ .

The number of valence electron of:

$C = 4$

$H = 1$

$O = 6$

The number of valence electrons in $C_2H_2O$ = $2\times 4+2\times 1+1\times 6 =16$

2 electrons are involved in each single bond between carbon and hydrogen and 4 electrons are involved in each double bond formed between carbon-carbon and carbon-oxygen. Hence, the total number of electrons involved in bond formation are 12 and rest 2 pair of electrons are present on oxygen as lone pair of electrons.

Therefore, the attached image is the Lewis structure of $C_2H_2O$ .

8 0

3 years ago

Help please thanks you

scoundrel [369]

Explanation:

Ok so water is H2O and cabon dioxide in the air is CO2, so the water goes through the carbon dioxide and makes acid rain H2SO4.

Now we have our limestone which is CaCO3.

What happens is that the acid breaks apart our limestone into Ca2+ and CO3 2-. This then reforms into Calcium bicarbonate Ca(CO3)2.

Calcium bicarbonate is soluble in water and is hence washed away by the rain eroding the limestone.

5 0

3 years ago

Many tests to distinguish aldehydes and ketones involve the addition of an oxidant. Only __________ can be easily oxidized becau

tatiyna

Answer:

Aldehydes
A hydrogen atom
Oxygen

Explanation:

Many tests to distinguish aldehydes and ketones involve the addition of an oxidant. Only aldehydes can be easily oxidized because there is a hydrogen atom next to the carbonyl and oxidation does not require oxygen

4 0

3 years ago

600.0 mL of air is at 20.0 c what is the volume at 60.0

pogonyaev

682mL

Explanation:

Given parameters:

Initial volume of air = 600mL

Initial temperature = 20°C

Final temperature = 60°C

Unknown:

Final volume = ?

Solution:

To solve this problem, we apply Charles's law';

Charles's law states that "at constant pressure, the volume of a given mass of gas is directly proportional to its temperature. "

Mathematically;

$\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }$

V₁ is the initial volume of air

T₁ is the initial temperature of air

V₂ is the final volume of air

T₂ is the final temperature of air

To proceed in solving this problem, we need to convert the given temperature to Kelvin;

T K = 273 + T°C

T₁ = 273 + 20 = 293K

T₂ = 273 + 60 = 333K

now input the parameters;

$V_{2} = \frac{V_{1} }{T_{1} } x T_{2} = \frac{600}{293 } x 333$

V₂ = 682mL

learn more:

Gas laws brainly.com/question/2438000

#learnwithBrainly

8 0

3 years ago