Question

600.0 mL of air is at 20.0 c what is the volume at 60.0

Answer 1

682mL

Explanation:

Given parameters:

Initial volume of air = 600mL

Initial temperature = 20°C

Final temperature = 60°C

Unknown:

Final volume = ?

Solution:

To solve this problem, we apply Charles's law';

Charles's law states that "at constant pressure, the volume of a given mass of gas is directly proportional to its temperature. "

Mathematically;

   $\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }$

V₁ is the initial volume  of air

T₁ is the initial temperature  of air

V₂ is the final volume  of air

T₂ is the final temperature of air

To proceed in solving this problem, we need to convert the given temperature to Kelvin;

T K = 273 + T°C

T₁  = 273 + 20 = 293K

T₂ = 273 + 60 = 333K

now input the parameters;

$V_{2} = \frac{V_{1} }{T_{1} } x T_{2} = \frac{600}{293 } x 333$

 V₂ = 682mL

learn more:

Gas laws brainly.com/question/2438000

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