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kakasveta [241]
3 years ago
13

Substances in a mixture keep their own properties. True or False?

Chemistry
1 answer:
Lady bird [3.3K]3 years ago
8 0
No they mix properties
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Use the drop-down menus to identify the effect of each mutation.
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Answer:

1 neutral

2 beneficial

3 harmful

Explanation:

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Which gas sample STP has the same total number of molecules at 2.0 L of CO2(g) at STP
zloy xaker [14]
<span>Answer 2 (2.0L of Cl2 (g)) is correct. Avogadro's hypothesis states that 2.0 L of Cl2 (g) occupies the same volume as 2.0 L of CO2</span>
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3 years ago
A chemist reacted 17.25 grams of sodium metal with an excess amount of chlorine gas. The chemical reaction that occurred is show
Afina-wow [57]

<u>Answer:</u> The actual yield of the product is 38.57 g

<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

We are given:

Given mass of Na = 17.25 g

Molar mass of Na = 23 g/mol

Putting values in equation 1, we get:

\text{Moles of Na}=\frac{17.25g}{23g/mol}=0.75mol

For the given chemical reaction:

2Na+Cl_2\rightarrow 2NaCl

By stoichiometry of the reaction:

2 moles of Na produces 2 moles of NaCl

So, 0.75 moles of Na will produce = \frac{2}{2}\times 0.75=0.75mol of NaCl

We know, molar mass of NaCl = 58.44 g/mol

Putting values in above equation, we get:

\text{Mass of NaCl}=(0.75mol\times 58.44g/mol)=43.83g

The percent yield of a reaction is calculated by using an equation:

\% \text{yield}=\frac{\text{Actual value}}{\text{Theoretical value}}\times 100 ......(1)

Given values:

Percent yield of the product = 88 %

Theoretical value of the product = 43.83 g

Plugging values in equation 1:

88\% =\frac{\text{Actual yield}}{43.83g}\times 100\\\\\text{Actual yield}=\frac{88\times 43.83}{100}=38.57g

Hence, the actual yield of the product is 38.57 g

3 0
3 years ago
PLEASE HELP ME WITH THID IFK IT!! ILL GIVE YOU EXTRA POINTS
xenn [34]
But a check at the bottom and x at the top
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3 years ago
If 20 grams of aluminum react with 200 grams of bromide to form aluminum bromide and no aluminum is left after the reaction, but
Varvara68 [4.7K]
The answer is: 197 grams

Why?

All 20 grams of aluminum was used to form aluminum bromide. Only 177 grams of bromide were used to make aluminum bromide, since 23 grams were left over.

20 grams + 177 grams = 197 grams, so the answer is 197 grams.
8 0
4 years ago
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