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4 years ago

What is instantaneous speed

1 answer:

5 0

What is instaneous speed? When the speed of an object is constantly changing, the instantaneous speed is the speed of an object at a particular

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Paragraph about how the constellations were used by ancient civilizations.

nata0808 [166]

Answer:

What does this mean ?

Explanation:

8 0

3 years ago

A charge of 25 nC is uniformly distributed along a straight rod of length 3.0 m that is bent into a circular arc with a radius o

Greeley [361]

Answer:

E = 31.329 N/C.

Explanation:

The differential electric field $dE$ at the center of curvature of the arc is

$dE = k\dfrac{dQ}{r^2}cos(\theta )$ (we have a cosine because vertical components cancel, leaving only horizontal cosine components of E. )

where $r$ is the radius of curvature.

Now

$dQ = \lambda rd\theta$ ,

where $\lambda$ is the charge per unit length, and it has the value

$\lambda = \dfrac{25*10^{-9}C}{3.0m} = 8.3*10^{-9}C/m.$

Thus, the electric field at the center of the curvature of the arc is:

$E = \int_{\theta_1}^{\theta_2} k\dfrac{\lambda rd\theta }{r^2} cos(\theta)$

$E = \dfrac{\lambda k}{r} \int_{\theta_1}^{\theta_2}cos(\theta) d\theta.$

Now, we find $\theta_1$ and $\theta_2$ . To do this we ask ourselves what fraction is the arc length 3.0 of the circumference of the circle:

$fraction = \dfrac{3.0m}{2\pi (2.3m)} = 0.2076$

and this is

$0.2076*2\pi =1.304$ radians.

Therefore,

$E = \dfrac{\lambda k}{r} \int_{\theta_1}^{\theta_2} cos(\theta)d\theta= \dfrac{\lambda k}{r} \int_{0}^{1.304}cos(\theta) d\theta.$

evaluating the integral, and putting in the numerical values we get:

$E = \dfrac{8.3*10^{-9} *9*10^9}{2.3} *(sin(1.304)-sin(0))\\$

$\boxed{ E = 31.329N/C.}$

4 0

3 years ago

A civil engineer must design a wheelchair-accessible ramp next to a set of steps leading up to a building. The height from the g

Westkost [7]

Answer:

A) B = 24 ft

B) H = 24.08 ft

C) M.A = 12.04

D) P = 13.7 lb

Explanation:

Minimum allowable length of base of ramp can be found as follows:

Slope = H/B

where,

Slope = 1/12

H = Height of Ramp = 2 ft

B = Length of Base of Ramp = ?

Therefore,

1/12 = 2 ft/B

B = 2 ft * 12

B = 24 ft

The length of the slope of ramp can be found by using pythagora's theorem:

L = √H² + B²

where,

H = Perpendicular = height = 2 ft

B = Base = Length of Base of Ramp = 24 ft

L = Hypotenuse = Length of Slope of Ramp = ?

Therefore,

H = √[(2 ft)² + (24 ft)²]

H = 24.08 ft

The mechanical advantage of an inclined plane is given by the following formula:

M.A = L/H

M.A = 24.08 ft/2 ft

M.A = 12.04

Another general formula for Mechanical Advantage is:

M.A = W/P

where,

W = Ideal Load = 165 lb

P = Ideal Effort Force = ?

Therefore,

12.04 = 165 lb/P

P = 165 lb/12.04

P = 13.7 lb

7 0

3 years ago

the jet plane travels along the vertical parabolic path. when it is at point a it has speed of 200 m/s, which is increasing at t

givi [52]

Explanation:

Here is the complete question i guess. The jet plane travels along the vertical parabolic path defined by y = 0.4x². when it is at point A it has speed of 200 m/s, which is increasing at the rate .8 m/s^2. Determine the magnitude of acceleration of the plane when it is at point A.

→ The tangential component of acceleration is rate of increase in the speed of plane so,

$a_{t} = v = 0.8 m/s^{2}$