To solve this problem we will apply the principle of conservation of energy and the definition of kinematic energy as half the product between mass and squared velocity. So,


Here,
m = Mass
V = Velocity
Replacing,


Therefore the final kinetic energy of the two car system is 72.6kJ
Answer:
W = 7056 J
Explanation:
Given that,
Mass of a load, m = 60 kg
Distance moved, d = 12 m
We need to find the amount of work. The work done by an object is given by :
W = Fd
So,
W = mg×d
W = 60 kg × 9.8 m/s²×12 m
W = 7056 J
So, the amount of work done is 7056 J.
A table would be the most appropriate because that way you can compare the data.
Answer:
Walking’ - If a handball player takes more than three steps without dribbling (bouncing the ball) or holds the ball for more than 3 seconds without bouncing it, shooting or passing, then that is deemed ‘walking' and possession is lost.
'Double dribble’ - Handball players cannot receive the ball and bounce it, then hold the ball, and bounce it again. This is termed ‘double dribble’ and is against the rules.
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Answer: 45 A
Explanation:
Primary only protection 3-phase
I = 3 phase kVA / ( 1.723 * V)
I = 30000 / ( 1.732 * 480 ) = 36.085 A
Table 450.3(B)
Currents of 9A or more column
primary only protection = 125%
Max OCPD pri = 125% of I = 1.25 * 36.085 = 45.11 A
Table 450.3(B) Note 1 does not apply, use next smaller Table 240.6(A)
Next smaller = 45 A