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Bingel [31]
3 years ago
6

Which chemical equation correctly represents the reaction that takes place when nitrogen gas and hydrogen gas are formed as ammo

nia decomposes? N(g) + H3(g) ? NH3(g) 2N(g) + 3H2(g) ? 2NH3(g) 2NH3(g) ? N2(g) + 2H3(g) 2NH3(g) ? N2(g) + 3H2(g)
Chemistry
1 answer:
Dima020 [189]3 years ago
5 0

Answer:

D. 2NH₃(g) ⟶ N₂(g) + 3H₂(g)

Explanation:

A chemical equation must show the correct formulas for reactants and products.

A and B are wrong, because they have NH₃ as a product.

C is wrong. H₃ does not exist.

A is correct. The equation for the decomposition of ammonia is

2NH₃(g) ⟶ N₂(g) + 3H₂(g)

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What mass of ammonia can be produced if 13.4 grams of nitrogen gas reacted ?
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Answer:

If 13.4 grams of nitrogen gas reacts we'll produce 16.3 grams of ammonia

Explanation:

Step 1: Data given

Mass of nitrogen gas (N2) = 13.4 grams

Molar mass of N2 = 28 g/mol

Molar mass of NH3 = 17.03 g/mol

Step 2: The balanced equation

N2 + 3H2 → 2NH3

Step 3: Calculate moles of N2

Moles N2 = Mass N2 / molar mass N2

Moles N2 = 13.4 grams / 28.00 g/mol

Moles N2 = 0.479 moles

Step 4: Calculate moles of NH3

For 1 mol N2 we need 3 moles H2 to produce 2 moles NH3

For 0.479 moles N2 we'll produce 2*0.479 = 0.958 moles

Step 5: Calculate mass of NH3

Mass of NH3 = moles NH3 * molar mass NH3

Mass NH3 = 0.958 moles * 17.03 g/mol

Mass NH3 = 16.3 grams

If 13.4 grams of nitrogen gas reacts we'll produce 16.3 grams of ammonia

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