The chemical compound's empirical formula is NS.
The chemical compound's molecular formula is N4S4.
<h3>What does a chemical empirical formula look like?</h3>
- The empirical formula of a compound that gives the proportion (ratios) of the elements in the complex but not the precise number or arrangement of atoms is known as an empirical formula.
- This would be the compound's element to whole number ratio with the lowest value.
<h3>What sort of empirical formula would that be?</h3>
- The chemical structure of glucose is C6H12O6. Every mole of carbon and oxygen is accompanied by two moles of hydrogen.
- Glucose has the empirical formula CH2O.
- Ribose has the chemical formula C5H10O5, which can be simplified to the empirical formula CH2O.
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the question you are looking for is
A compound containing only sulfur and nitrogen is 69.6% S by mass; the molar mass is 184 g/mol. What are the empirical and molecular formulas of the compound?
Answer:
-2, -1, 0, 1, 2
Explanation:
There are four types of quantum numbers;
1) Principal quantum number (n)
2) Azimuthal quantum number (l)
3) magnetic quantum number (ml)
4) Spin quantum number (s)
The azimuthal quantum number (l) describes the orbital angular momentum and shape of an orbital while the magnetic quantum number shows the projections of the orbital angular momentum along a specified axis. This implies that the magnetic quantum number shows the orientation of various orbitals along the Cartesian axes. The values of the magnetic quantum number ranges from -l to + l
For l= 2, the possible values of the magnetic quantum number are; -2, -1, 0, 1, 2
Answer: 5
Explanation: this is because the energy level of the emitted of absorbed photon increases as the number of electron shell decreases, thereby making the inner shell have higher energy than other shells
Answer:
11.31 g.
Explanation:
Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.
M = (no. of moles of solute)/(V of the solution (L)).
<em>∴ M = (mass/molar mass)of NaCl/(V of the solution (L)).</em>
<em></em>
<em>∴ mass of NaCl remained after evaporation of water = (M)(V of the solution (L))(molar mass)</em> = (0.45 M)(0.43 L)(58.44 g/mol) = <em>11.31 g.</em>
The answes are
C)
Then it is
)A
Im doing this for class too bruh
