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3 years ago

Identify the parts of the electromagnetic spectrum, both visible and invisible.

2 answers:

8 0

The visible light spectrum is a fractional part of the electromagnetic spectrum, which is visible due to our eyes, which are light receptors. Invisible spectrum are things like UV spectrum which falls outside the human visible range.

Kaylis [27]3 years ago

4 0

Radio
Microwave
Infrared (heat)
Visible (visible part)
Ultraviolet
X-ray
Gamma ray

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A 500 kg satellite experiences a gravitational force of 3000 N, while moving in a circular orbit around the earth. Determine the

natka813 [3]

Answer:

Speed of the satellite V = 6.991 × 10³ m/s

Explanation:

Given:

Force F = 3,000N

Mass of satellite m = 500 kg

Mass of earth M = 5.97 × 10²⁴

Gravitational force G = 6.67 × 10⁻¹¹

Find:

Speed of the satellite.

Computation:

Radius r = √[GMm / F]

Radius r = √[(6.67 × 10⁻¹¹ )(5.97 × 10²⁴)(500) / (3,000)

Radius r = 8.146 × 10⁶ m

Speed of the satellite V = √rF / m

Speed of the satellite V = √(8.146 × 10⁶)(3,000) / 500

Speed of the satellite V = 6.991 × 10³ m/s

8 0

3 years ago

A 1.2 x10 3 kilogram automobile in motion strikes a 1.0 x 10 -4 kilogram insect as a result the insect is accelerated at a rate

Mariana [72]

According to Newton's second law, the force applied to an object is equal to the product between the mass of the object and its acceleration:
$F=ma$
where F is the magnitude of the force, m is the mass of the object and a its acceleration.

In this problem, the object is the insect, with mass $m=1.0 \cdot 10^{-4} kg$ . The acceleration of the insect is $a=1.0 \cdot 10^2 m/s^2$ , therefore we can calculate the force exerted by the car on the insect:
$F=ma=(1.0 \cdot 10^{-4} kg)(1.0 \cdot 10^2 m/s^2)=0.01 N$

How do we find the force exerted by the insect on the car?
According to Newton's third law (known as action-reaction law), when an object A exerts a force on an object B, object B also exerts a force equal and opposite on object A. Therefore, the force exerted by the insect on the car is equal to the force exerted by the car on the object, so it is 0.01 N.

6 0

3 years ago

Which term best describes those processes that move weathered rock materials and soils downslope?

mote1985 [20]

Answer:

mass wasting

Explanation:

5 0

2 years ago

A car accelerates from 10m/s to 20m/s over a distance of 80m. What is its acceleration?

Lina20 [59]

Answer:

0.125m/s^2

Explanation:

20-10=10

10 divided by 80=0.125m/s^2

5 0

3 years ago

A 2.0-cm-diameter parallel-plate capacitor with a spacing of 0.50 mm is charged to 200 V. What are (a) the total energy stored i

Debora [2.8K]

Answer:

(A) Total energy will be equal to $0.044\times 10^{-5}J$

(b) Energy density will be equal to $0.0175J/m^3$

Explanation:

We have given diameter of the plate d = 2 cm = 0.02 m

So area of the plate $A=\pi r^2=3.14\times 0.02^2=0.001256m^2$

Distance between the plates d = 0.50 mm = $0.50\times 10^{-3}m$

Permitivity of free space $\epsilon _0=8.85\times 10^{-12}F/m$

Potential difference V =200 volt

Capacitance between the plate is equal to $C=\frac{\epsilon _0A}{d}=\frac{8.85\times 10^{-12}\times 0.001256}{0.50\times 10^{-3}}=0.022\times 10^{-9}F$

(a) Total energy stored in the capacitor is equal to

$E=\frac{1}{2}CV^2$

$E=\frac{1}{2}\times 0.022\times 10^{-9}\times 200^2=0.044\times 10^{-5}J$

(b) Volume will be equal to $V=Ad$ , here A is area and d is distance between plates

$V=0.001256\times 0.02=2.512\times 10^{-5}m^3$

So energy density $=\frac{Energy}{volume}=\frac{0.044\times 10^{-5}}{2.512\times 10^{-5}}=0.0175J/m^3$

7 0

3 years ago