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GrogVix [38]
3 years ago
13

You hold a 0.125 kg glider A and a 0.500 kg glider B at rest on an air track with a compressed spring of negligible mass between

them. When you release the gliders, the spring pushes them apart so that they move in opposite directions. When glider A has moved 0.960 m to the left from its starting position, how far to the right from its starting position has glider B moved?
Physics
1 answer:
o-na [289]3 years ago
8 0

Answer:

Magnitude |VB| = 0.32 m/s

and

Direction is to the left

Explanation:

given data

glider A mass = 0.125 kg

glider B mass = 0.500 kg

glider A move = 0.960 m to the left

solution

we use here Conservation of momentum  that is

M1 × U1 + M2 × U2 =M1 × V1 + M2 × V2    ........................1

put here value and we get

0.125 × 0 + 0.500 × 0 = 0.125 × 0.960 + 0.375 × VB

VB = −0.32  m/s

Magnitude |VB| = 0.32 m/s

and

Direction is to the left

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givi [52]

Answer:

From the given choices, the healthy snack that can provide protein after physical activity is the third option, yogurt. Yogurts are derived from fermentation of raw materials by the healthy bacteria, usually of lactobacillus origin. Other items in the choices are not able to provide protein. 

Explanation:

4 0
3 years ago
Which type of comb would be best to use in the winter, a plastic comb or a glass comb? Explain using the Triboelectric series.
leonid [27]

Answer:

I'm not sure how to use it using the Series, but it would be the plastic comb

Explanation:

In the winter, it's likely to be cold and the glass would absorb that energy, also making it cold. in order to be able to hold it, you would need something warm, thus making the plastic one the better option as it is less likely to absorb the cold energy

7 0
3 years ago
(a) a light-rail commuter train accelerates at a rate of 1.15 m/s2. how long does it take it to reach its top speed of 80.0 km/h
snow_lady [41]
A = 1.15m/s2, Vf = 80.0km/h --> we need it in m/s, so:
Vf = 80km/h × 1000m/1km × 1h/3600s
= 22.22m/s
Top speed = Vf, initial speed = Vi
time (t) = V(Vf-Vi) ÷ a
t = (22.22-0)m/s ÷ 1.15m/s2
t = 22.22m/s × s2/1.15m
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6 0
3 years ago
3.) An engineer is designing the runway for an airport. Of the planes that will use the airport,
scoray [572]

Answer: 704

Explanation:Vi = 0 m/s

vf = 65 m/s

a = 3 m/s2

d = ??

vf2 = vi2 + 2*a*d

(65 m/s)2 = (0 m/s)2 + 2*(3 m/s2)*d

4225 m2/s2 = (0 m/s)2 + (6 m/s2)*d

(4225 m 2/m2)/(6 m/s2) = d

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5 0
3 years ago
Read 2 more answers
A spherically spreading EM wave comes from an 1800-W source. At a distance of 5.0 m, what is the intensity, and what is the rms
Aleonysh [2.5K]

Explanation:

It is given that,

Power of EM waves, P = 1800 W

We need to find the intensity at a distance of 5 m. Also, the rms value of the electric field.

Intensity,

I=\dfrac{P}{4\pi r^2}\\\\I=\dfrac{1800}{4\pi\times (5)^2}\\\\I=5.72\ W/m^2

The formula that is used to find the rms value of the electric field is as follows :

I=\epsilon_o cE^2_{rms}

c is speed of light and \epsilon_o is permittivity of free space

So,

E_{rms}=\sqrt{\dfrac{I}{\epsilon_o c}}\\\\E_{rms}=\sqrt{\dfrac{5.72}{8.85\times 10^{-12}\times 3\times 10^8}}\\\\E_{rms}=46.41\ V/m

Hence, this is the required solution.

4 0
3 years ago
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