The next step is -748 divide by -11 is 68 m (answer) the pic got cropped sorry
Complete question is;
A 50.-ohm resistor, an unknown resistor R, a 120-volt source, and an ammeter are
connected in a complete circuit. The ammeter reads 0.50 ampere.
A) Calculate the equivalent resistance of the circuit shown.
B) Determine the resistance of resistor R shown in the diagram.
Answer:
A) R_eq = 240 Ω
B) R = 190 Ω
Explanation:
A) To get the equivalent resistance, we will use the formula;
R = V/I
Where;
V is Voltage
I is current
R is equivalent resistance
From the question, V = 120 V and I = 0.5A
Thus;
R_eq = 120/0.5
R_eq = 240 Ω
B) From the image, we see that the resistors are connected in series.
Formula for resistors in series is;
R = R1 + R2 +..... Rn
Thus;
240 = 50 + R
R = 240 - 50
R = 190 Ω
Answer: 1.59 sec
Explanation:
The kinetic energy contained in the rotation of the cylinder is 1/2 m v^2
The kinetic energy of translation is also 1/2 m v^2
so the total energy is m v^2
The force applied is mg sin (theta)
= m x 9.8 x 1/2
= 4.9 m
Now equate
F x d = m v^2
4.9 m x 3.1 = m v^2
v^2 = 4.9 x 3.1
v = sqrt(4.9 x 3.1) = 3.9 m/s
Acceleration.
V^2 = 2 a s
4.9 x 3.1 = 2 x a x 3.1
4.9 = 2 a
a = 2.45 m/s^2
Time
T = v/a
= 3.9/2.45
= 1.59 sec
<span>Answer: 124eV
Explanation: Apply Planck - Einstein Relation to calculate the energy of an X-Ray photon that has a frequency of 3.00 x 10^16 Hz and the energy of a photon is proportional to its frequency
E= hv
where E - the energy of the photon
h - Planck's constant, equal to 6.626 x 10^-34 Js
v - the frequency of the photon
and 1 Hz is equal to 1 s^-1
Thus E= 1.988 x 10^-17J
Now convert the energy of photon from joules to eV
Therefore we get 1.988 x 10^-17J x ( 1 eV / 1.6022 x 10^-19 J)
= 124 eV.</span>