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3 years ago

What is the spring constant for a supermarket scale that stretches 0.01 m when a force of 4 N is applied

Physics

2 answers:

Greeley [361]3 years ago

6 0

Answer: The spring constant for the supermarket scale is 400 N/m.

Explanation:

To calculate the spring constant, we use Hooke's Law. The formula for Hooke's law is:

$F=kx$

where, F = Force applied on the spring = 4N

k = Spring constant = ? N/m

x = Compression or extension of the spring = 0.01m

Putting values in above equation, we get:

$400N=k\times 0.01m\\\\k=400N/m$

Hence, the spring constant for the supermarket scale is 400 N/m.

Nikolay [14]3 years ago

3 0

The answer to the question is 400 N.

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3 years ago

how much work does tension do on the laptop as it moves 2.0 mm ? express your answer with the appropriate units.

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The work done by tension force of 14N applied on the laptop by a rope as it moves 2.0 mm up the slope is 0.028 J

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W = Work done

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θ = 0

W = 14 * 0.002 * 1

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1 year ago

Can work done=mass*acceleration*displacement(work=m*a*s)

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3 years ago

To meet a U.S. Postal Service requirement, employees' footwear must have a coefficient of static friction of 0.5 or more on a sp

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Answer:

0.79 s

Explanation:

We have to calculate the employee acceleration, in order to know the minimum time. According to Newton's second law:

$\sum F_x:f_{max}=ma_x\\\sum F_y:N-mg=0$

The frictional force is maximum since the employee has to apply a maximum force to spend the minimum time. In y axis the employee's acceleration is zero, so the net force is zero. Recall that $f_{max}=\mu N$

Now, we find the acceleration:

$\mu N=ma_x\\\mu mg=ma_x\\a_x=\mu g\\a_x=0.83(9.8\frac{m}{s^2})\\a_x=8.134\frac{m}{s^2}$

Finally, using an uniformly accelerated motion formula, we can calculate the minimum time. The employee starts at rest, thus his initial speed is zero:

$x=v_0t+\frac{1}{2}a_xt^2\\2x=a_xt^2\\t=\sqrt{\frac{2x}{a}}\\t=\sqrt{\frac{2(3.2m)}{8.134\frac{m}{s^2}}}\\t=0.79 s$

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3 years ago