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Natasha_Volkova [10]
3 years ago
9

What is the spring constant for a supermarket scale that stretches 0.01 m when a force of 4 N is applied

Physics
2 answers:
Greeley [361]3 years ago
6 0

Answer: The spring constant for the supermarket scale is 400 N/m.

Explanation:

To calculate the spring constant, we use Hooke's Law. The formula for Hooke's law is:

F=kx

where, F = Force applied on the spring = 4N

k = Spring constant = ? N/m

x = Compression or extension of the spring = 0.01m

Putting values in above equation, we get:

400N=k\times 0.01m\\\\k=400N/m

Hence, the spring constant for the supermarket scale is 400 N/m.

Nikolay [14]3 years ago
3 0
The answer to the question is 400 N. 
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A chemical equation lists NaHCO3(s) as a reactant. What does (s) indicate?
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The (s) indicates that the state of matter for NaHCO3 is solid.

Explanation:

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The aircraft wing from problem 6 experiences temperature extremes that span 210 degrees Celsius. The component for the wing will
ExtremeBDS [4]

Answer:

α = 2,857 10⁻⁵ ºC⁻¹

Explanation:

The thermal expansion of materials is described by the expression

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in the case of the bar the expansion is

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         ΔL=   1.002 -1

         ΔL = 0.002 m

the temperature variation is

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5 0
3 years ago
A seesaw is 4.0m long with a pivot at its midpoint. A boy who weighs 400N sits at a distance of 1.5m from the pivot. His sister
bezimeni [28]

Answer:

the girl must sit 2 cm from the pivot at the opposite end of the seesaw.

Explanation:

Given;

length of the seesaw, L = 4.0 m

weight of the boy, W₁ = 400 N

position of the boy from the pivot, d₁ = 1.5 m

weight of her sister, W₂ = 300 N

First, make a sketch of this information given;

                 0---0.5m---------------------Δ--------------------------4m

                         ↓<--------1.5m-------> <---------x--------->↓

                        400 N                                          300N

Apply the principle of moment about the pivot, to determine the value of x;

Sum of anticlockwise moment = sum of clockwise moment

400(1.5) = 300(x)

600 = 300x

x = 600/300

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Thus, the girl must sit 2 cm from the pivot at the opposite end of the seesaw.

8 0
3 years ago
A roller coaster is traveling at 13 m/s when it approaches a hill that is 400 m long. Heading down the hill, it accelerates at 4
SIZIF [17.4K]

Answer:

The  value is    v = 47 \  m/s

Explanation:

From the question we are told that

   The initial  speed of the roller coaster is u =  13 \  m/s

    The  length of the hill is  l   = 400 \  m

    The  acceleration of the  roller coaster is a=4.0 \ m/s^2

Generally the acceleration is mathematically represented as

      a =  \frac{ v - u}{ t_f -  t_i }

Here  t_i is the initial time which is equal to zero

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          v_f  =  \frac{d}{ t_f}

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      4 =  \frac{400 - 13t_f}{ t_f} *  \frac{1}{t_f}

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Generally  time cannot be negative so

       t_f =  8.5 \ s

Generally the  final velocity is mathematically represented as

         v = \frac{400}{8.5}

         v = 47 \  m/s

       

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