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4 years ago

Will an object with a density of 0.97 g/ml float or sink in water

2 answers:

4 0

0.97 g/ml

Since 1000cm³ = 1 litre. And 1ml = 10^-3 l = 10^-3 * 1000 cm³ = 1cm³

0.97 g/ml = 0.97 g/cm³

And since it is less than density of water which is 1.00 g/cm³. The object will rest on the water.

It will not float. It will float if its density is equal to density of water, and would sink if its density is greater than that of water and would rest on the water if its density is less than that of water.

bellaAAAA3 years ago

0 0

WHAT IS THE ANSWER

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What type of bond exists between the atoms in a molecule of N2?

vivado [14]

Answer:

covalent bonds

Explanation:

Nitrogen atoms will form three covalent bonds (also called triple covalent) between two atoms of nitrogen because each nitrogen atom needs three electrons to fill its outermost shell.

(if it is still confusing i have another way of explaining so jus let me know :)

6 0

3 years ago

What is the pH of a solution of KOH with a hydroxide concentration of [OH⁻] = 1.10 x 10⁻⁴

olga2289 [7]

Answer:

$p[H+] = 10.042$

Explanation:

As we know that

$pKw = pH + pOH$ ......eq (1)

we will calculate the pH of OH- and then we will calculate the pH of H+

So p[OH-] $= - log [1.10 * 10^{-4}]$

Solving the right side of the equation, we get

p[OH-]

$= - [-3.958]\\= 3.958$

Now we know that

$pKw = 14.0$

Substituting the value of pOH in the above equation, we get -

$14.0 = p[H+] + 3.958\\p[H+] = 14 - 3.958\\p[H+] = 10.042$

3 0

3 years ago

5. In the industrial synthesis of nylon, one of the starting materials, adipic

sukhopar [10]

Answer:

ligmaballlschock3 on a cocktail

Explanation:

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2 years ago

For a particular reaction, Δ=−111.4 kJ and Δ=−25.0 J/K.

vichka [17]

Answer:

$\Delta G =-103.95kJ$

Explanation:

Hello there!

In this case, since the thermodynamic definition of the Gibbs free energy for a change process is:

$\Delta G =\Delta H-T\Delta S$

It is possible to plug in the given H, T and S with consistent units, to obtain the correct G as shown below:

$\Delta G =-111.4kJ-(298K)(-25.0\frac{J}{K}*\frac{1kJ}{1000J} )\\\\\Delta G =-103.95kJ$

Best regards!

6 0

3 years ago

A cylinder containing carbon dioxide of volume 20 L at 2.0 atm was connected to another cylinder of certain volume at constant t

den301095 [7]

Answer:

The volume of the second cylinder is 80 liters

Explanation:

We use the Boyle-Mariotte formula, according to which the pressure and volume of a gas are inversely related, keeping the temperature constant: P1 x V1 = P2xV2. We convert the pressure in mmHg to atm:

760 mmHg-----1 atm

380mmHg------x= (380mmHgx1atm)/760mmHg=0,5 atm

P1xV1=P2xV2

2 atmx20 L= 0,5atm x V2 V2=(2 atmx20 L)/0,5atm=80L

8 0

3 years ago