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Leto [7]
3 years ago
14

____________ occurs when an energy source transfers heat directly to another object through space; an example would be an object

becoming warm by sitting in the sunshine. a. conduction c. convection b. radiation d. heat Please select the best answer from the choices provided A B C D
Physics
2 answers:
lapo4ka [179]3 years ago
5 0
B is the answer Radiation

Korvikt [17]3 years ago
3 0

Answer:

b. radiation

Explanation:

In order to answer correctly, let's describe the three method of transfer of heat:

1) Conduction: conduction occurs when heat is transferred through two materials which are directly in contact with each other. The transfer of heat occurs because the kinetic energy of the particles in the first medium is transferred through collisions to the particles in the second medium. Conduction can occurs in solids, liquids and gases, but it cannot occur in empty space

2) Convection: convection occurs when a fluid is heated by an external source. In this case, the particles of the fluid closer to the source of heat are heated faster, therefore the area of fluid near the source becomes warmer and less dense, therefore rises and it is replaced by the colder parts of the fluid, and so on, creating a convection current. Convection occurs only in fluids (liquids or gases)

3) Radiation: radiation occurs when a source emits electromagnetic radiation, which carries energy through space and materials. Therefore, radiation can also occur in empty space.

Therefore, the example described:

an energy source transfers heat directly to another object through space; an example would be an object becoming warm by sitting in the sunshine.

Is an example of heat transferred through radiation.

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3 0
3 years ago
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In 2005 astronomers announced the discovery of a large black hole in the galaxy Markarian 766 having clumps of matter orbiting a
IRISSAK [1]

A. 4.64\cdot 10^{11}m

The orbital speed of the clumps of matter around the black hole is equal to the ratio between the circumference of the orbit and the period of revolution:

v=\frac{2\pi r}{T}

where we have:

v=30,000 km/s = 3\cdot 10^7 m/s is the orbital speed

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T=27 h \cdot 3600 =97,200 s is the orbital period

Solving for r, we find the distance of the clumps of matter from the centre of the black hole:

r=\frac{vT}{2\pi}=\frac{(3\cdot 10^7 m/s)(97200 s)}{2\pi}=4.64\cdot 10^{11}m

B. 6.26\cdot 10^{36}kg, 3.13\cdot 10^6 M_s

The gravitational force between the black hole and the clumps of matter provides the centripetal force that keeps the matter in circular motion:

m\frac{v^2}{r}=\frac{GMm}{r^2}

where

m is the mass of the clumps of matter

G is the gravitational constant

M is the mass of the black hole

Solving the formula for M, we find the mass of the black hole:

M=\frac{v^2 r}{G}=\frac{(3\cdot 10^7 m/s)^2(4.64\cdot 10^{11} m)}{6.67\cdot 10^{-11}}=6.26\cdot 10^{36}kg

and considering the value of the solar mass

M_s = 2\cdot 10^{30}kg

the mass of the black hole as a multiple of our sun's mass is

M=\frac{6.26\cdot 10^{36} kg}{2\cdot 10^{30} kg}=3.13\cdot 10^6 M_s

C. 9.28\cdot 10^9 m

The radius of the event horizon is equal to the Schwarzschild radius of the black hole, which is given by

R=\frac{2MG}{c^2}

where M is the mass of the black hole and c is the speed of light.

Substituting numbers into the formula, we find

R=\frac{6.26\cdot 10^{36} kg)(6.67\cdot 10^{-11})}{(3\cdot 10^8 m/s)^2}=9.28\cdot 10^9 m

8 0
3 years ago
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Strike441 [17]

Answer:

1 cycle every 2 seconds if that is what it is asking. So you have to do 2 x 30 and you will get 60 so ur awnser is 60

Explanation:

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It would go to the positive charge im like 99% sure of that
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