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larisa [96]
3 years ago
9

The temperature outside is 39 ∘C , and the air pressure is 0.800 atm . Your neighbor, who released the balloon, tells you that h

e filled it with 3.80 moles of gas. What is the volume of gas inside this balloon?
Chemistry
1 answer:
Inessa05 [86]3 years ago
7 0

Answer:

Ballx

Explanation:

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Crude oil pumped out of the ground may be accompanied by formation water, a solution that contains high concentrations of nacl a
djverab [1.8K]

solution:

the change in the boiling point is given as,

dTbp =2.30°c

elevation constant for the solvent is given by,

kb=0.512°c/m

molality=\frac{dTBP}{KB\times m}\\=\frac{2.30}{0.512c/m}

= 4.49m

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3 years ago
A beaker of water has a volume of 125mL and a density of 1.0g/mL. Calculate the mass of the water.​
Oksanka [162]

Answer: 125 grams

Explanation:  (125mL)*(1.0g/mL) = 125g

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If a stone with an original velocity of 0 is falling from a ledge and takes 8 seconds to hit the ground what is the final veloci
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Also 0 as it hits the ground and stops
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What is the amount of heat required to change one mole of a substance from the solid to liquid state known as?
Alla [95]

melting point because the melting point is the heat required to make an object melt anything less than this poitn will not make the substence melt.

5 0
3 years ago
Read 2 more answers
In the absence of sodium methoxide, the same alkyl bromide gives a different product. Draw an arrowpushing mechanism to account
hoa [83]

Answer:

See explanation below

Explanation:

The question is incomplete, cause you are not providing the structure. However, I found the question and it's attached in picture 1.

Now, according to this reaction and the product given, we can see that we have sustitution reaction. In the absence of sodium methoxide, the reaction it's no longer in basic medium, so the sustitution reaction that it's promoted here it's not an Sn2 reaction as part a), but instead a Sn1 reaction, and in this we can have the presence of carbocation. What happen here then?, well, the bromine leaves the molecule leaving a secondary carbocation there, but the neighbour carbon (The one in the cycle) has a more stable carbocation, so one atom of hydrogen from that carbon migrates to the carbon with the carbocation to stabilize that carbon, and the result is a tertiary carbocation. When this happens, the methanol can easily go there and form the product.

For question 6a, as it was stated before, the mechanism in that reaction is a Sn2, however, we can have conditions for an E2 reaction and form an alkene. This can be done, cause the extoxide can substract the atoms of hydrogens from either the carbon of the cycle or the terminal methyl of the molecule and will form two different products of elimination. The product formed in greater quantities will be the one where the negative charge is more stable, in this case, in the primary carbon of the methyl it's more stable there, so product 1 will be formed more (See picture 2)

For question 6b, same principle of 6a, when the hydrogen migrates to the 2nd carbocation to form a tertiary carbocation the methanol will promove an E1 reaction with the vecinal carbons and form two eliminations products. See picture 2 for mechanism of reaction.

3 0
3 years ago
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