Answer:
21.2 moles.
Explanation:
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In this case, for the given chemical reaction, we can see there is a 1:4 mole ratio between tetraphosphorous decaoxide and phosphorous; therefore, the following proportional factor provides the requested moles of phodphorous:
![n_P=5.3molP_4O_{10} *\frac{4molP}{1molP_4O_{10}} \\\\n_P=21.2molP](https://tex.z-dn.net/?f=n_P%3D5.3molP_4O_%7B10%7D%20%2A%5Cfrac%7B4molP%7D%7B1molP_4O_%7B10%7D%7D%20%5C%5C%5C%5Cn_P%3D21.2molP)
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Answer:
The behavior of molecules in different phases of matter represents a balance between the kinetic energies of the molecules and the attractive forces between them. All molecules are attracted to each other. The molecules are in the solid-state. At higher temperatures, the kinetic energy of the molecules is higher.
Answer:
A. 32.06 g/mol
Explanation:
The molar mass units are always g/mol