Answer:
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Explanation:
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Answer: if the pressure in the container is doubled, then the temperature will double too.
Justification:
You can rely on Gay-Lussac's law for ideal gases to answer the question.
According to that law, the pressure and temperature of a fixed amount of gas in a closed rigid container (constant volume) varie in direct proportion.
Mathematically, you can write in this way:
P/T = k
P₁ / T₁ = P₂ / T₂
That means, that if the pressure in the container is doubled, then the temperature will double too.
You can see that mathematically:
P₂ = 2 P₁
T₂ = (T₁ / P₁)(P₂) = (T₁ / P₁) (2 P₁) = 2 T₁
Answer:
The resistivity is ![\rho = 2.5 *10^{-8} \ \Omega \cdot m](https://tex.z-dn.net/?f=%5Crho%20%20%3D%20%202.5%20%2A10%5E%7B-8%7D%20%5C%20%20%5COmega%20%5Ccdot%20m)
Explanation:
From the question we are told that
The magnitude of the electric field is ![E = 6.2 V/m](https://tex.z-dn.net/?f=E%20%3D%20%206.2%20V%2Fm)
The current density is ![J = 2.4 *10^{8} \ A/m^2](https://tex.z-dn.net/?f=J%20%20%3D%20%202.4%20%2A10%5E%7B8%7D%20%5C%20%20A%2Fm%5E2)
Generally the resistivity is mathematically represented as
![\rho = \frac{E}{J}](https://tex.z-dn.net/?f=%5Crho%20%20%3D%20%20%5Cfrac%7BE%7D%7BJ%7D)
substituting values
![\rho = \frac{6.2}{2.4 *10^{8}}](https://tex.z-dn.net/?f=%5Crho%20%20%3D%20%20%5Cfrac%7B6.2%7D%7B2.4%20%2A10%5E%7B8%7D%7D)
![\rho = 2.5 *10^{-8} \ \Omega \cdot m](https://tex.z-dn.net/?f=%5Crho%20%20%3D%20%202.5%20%2A10%5E%7B-8%7D%20%5C%20%20%5COmega%20%5Ccdot%20m)