You are given a copper bar of dimensions 3 cm × 5 cm × 8 cm and asked to attach leads to it in order to make a resistor. (a) If
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Answer:
The activation energy for this reaction, Ea = 159.98 kJ/mol
Explanation:
Using the Arrhenius equation as:
Where, Ea is the activation energy.
R is the gas constant having value 8.314 J/K.mol
K₂ and K₁ are the rate constants
T₂ and T₁ are the temperature values in kelvin.
Given:
K₂ = 8.66×10⁻⁷ s⁻¹ , T₂ = 425 K
K₁ = 3.61×10⁻¹⁵ s⁻¹ , T₁ = 298 K
Applying in the equation as:
Solving for Ea as:
Ea = 159982.23 J /mol
1 J/mol = 10⁻³ kJ/mol
Ea = 159.98 kJ/mol
Answer:
Efriction = 768.23 [kJ]
Explanation:
In order to solve this problem we must use the principle of energy conservation. Where it tells us that the energy of a system plus the work applied or performed by that system, will be equal to the energy in the final state. We have two states the initial at the time of the balloon jump and the final state when the parachutist lands.
We must identify the types of energy in each state, in the initial state there is only potential energy, since the reference level is in the ground, at the reference point the potential energy is zero. At the time of landing the parachutist will only have potential energy, since it reaches the reference level.
The friction force acts in the opposite direction to the movement, therefore it will have a negative sign.
where:
m = mass = 56 [kg]
h = elevation = 1400 [m]
v = velocity = 5.6 [m/s]
Answer:
The force is
Explanation:
From the question we are told that
The first diameter is
The second diameter is
Generally the first area is
=>
=>
The second area is
For a hydraulic press the pressure at both end must be equal .
Generally pressure is mathematically represented as
=>
=>
=>
Answer:
q = -7.691 × C
so magnitude of charge is 7.691 × C
and negative sign mean charge is negative potential
Explanation:
given data
electric potential = −2.36 V
distance = 2.93 mm = 2.93 × m
to find out
What are the sign and magnitude of a point charge
solution
we know here that electric potential due to charge is
V = ..............................1
here k is coulomb force that is 8.99 × Nm²/C² and r is distance and q is charge and V is electric potential
put here all value we get q in equation 1
V =
-2.36 =
q = -7.691 × C
so magnitude of charge is 7.691 × C
and negative sign mean charge is negative potential