Actual question from source:-
A 3.96x10-4 M solution of compound A exhibited an absorbance of 0.624 at 238 nm in a 1.000 cm cuvette. A blank had an absorbance of 0.029. The absorbance of an unknown solution of compound A was 0.375. Find the concentration of A in the unknown.
Answer:
Molar absorptivity of compound A = 
Explanation:
According to the Lambert's Beer law:-
Where, A is the absorbance
l is the path length
is the molar absorptivity
c is the concentration.
Given that:-
c = 
Path length = 1.000 cm
Absorbance observed = 0.624
Absorbance blank = 0.029
A = 0.624 - 0.029 = 0.595
So, applying the values in the Lambert Beer's law as shown below:-

<u>Molar absorptivity of compound A =
</u>
The answer is: 4) " 2.7 * 10⁵ mg " .
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Explanation:
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Since all answer choices given are in "mg" ("milligrams"); we need to convert our given value, "0.27 kg" ("kilograms") to "mg" ("milligrams").
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Note the following "exact value" conversions:
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1000 mg = 1 g ;
1000 g = 1 kg.
(0.27 kg) (1000 g / 1 kg) (1000 mg/1 g) = __?__ mg ;
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The units of "kg", and "g" cancel to "1" and we are left with:
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0.27 * 1000 * 1000 mg = 270,000 mg = 2.7 * 10<span>⁵ </span> mg ; which is:
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→ Answer choice: # 4 .
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Answer: <u>Endonuclease enzymes used in molecular biology that cut DNA at specified points.</u>
Explanation:
Enzymes are specific protein types which bind to a substrate within a reaction, to increase the rate of reaction within the solution- they speed up the rate of reaction.
Restriction enzymes are bacteria-derived enzymes; these make cuts on deoxyribonucleic acid molecules or DNA. These are also called restriction endonucleases. They are utilized in molecular biology for DNA cloning and sequencing and cut DNA into smaller pieces called fragments.
Restriction enzymes make directed cuts on DNA molecules. They precisely target sites on DNA to produce mostly identical or homogenous, discrete fragments of equal sizes, producing blunt or sticky ends. In order to do this, they recognize sequences of nucleotides that correspond with a complementary sequence on the endonuclease called restriction sites.
There are several kinds that may require cofactors (chemical or metallic compounds that aid in enzyme activity) :
- Type I: cleave far away from the recognition site; require ATP and SAMe S-Adenosyl-L-Methionine
- Type II: cleave near to the site; require Magnesium
- Type III: cleave near to the site; require ATP which is not hydrolysed but SAMe S-Adenosyl-L-Methionine is optional
- Type IV: cleavage targeted to DNA that have undergone post transcriptional modification through certain types of methylation (addition of a methyl group)
First is homogeneous and so is the third. second is heterogeneous